How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
In the diagram, |SP| = |SR| and < PRS = 50o. Calculate < PQR
120o
110o
100o
80o
Correct answer is C
< PRS = RPS = 50o (base of isosceles)
RPS = 50o; < RSP + < PRS + < RPS = 180(sum of < s in a triangle)
< RPS + 50 + 50 = 180
< RSP = 180 - 100 = 80
then < PQR + < RSp = 180 (opp. < S of cyclic quad.)
< PQR + 80 = 180o
< PQR = 180 - 80
= 100
From the diagram, find the value of x in the diagram.
80o
70o
55o
35o
Correct answer is B
y + 110o = 180o(angles on a straight line)
y = 180 - 110
= 70o
x = y(corresponding angles)
x = 70o
24cm2
12cm2
10cm2
6cm2
Correct answer is B
Since tan y = \(\frac{2}{3}\) and LN = 4
tan y = \(\frac{2 \times 4}{3 \times 4} = \frac{8}{12} = \frac{4}{6}\)
then tan y = \(\frac{opp}{adj}\)
MN = 6cm
Area of angle LMN = \(\frac{1}{2}\)bh
= \(\frac{1}{2} \times 6 \times 4\)
= 12cm3
80.00cm
8.00cm
0.80cm
0.08cm
Correct answer is B
Vol. of cylinder = \(\pi r^2h\) = 1200cm2
Area of base = \(\pi^2\) = 150cm2
h = \(\frac{\pi r^2}{\pi r^2} = \frac{1200}{150}\)
= 8.00cm
422.92cm
149.92cm
44.00cm
43.96cm
Correct answer is C
r = 16, R = 23; 2\(\pi R - 2 \pi r\)
= 2\(\pi(R - r)\)
= 2 x \(\frac{22}{7} (23 - 16)\)
= 2 x \(\frac{22}{7} \times (7)\)
= 44cm