How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
5\(\frac{1}{2}cm\)
4\(\frac{2}{3}cm\)
3\(\frac{1}{2}cm\)
2\(\frac{1}{3}cm\)
Correct answer is D
Length of arc = circumference of the base of the
cone \(\frac{\theta}{360} \times 2\pi R = 2 \pi r\)
\(\frac{\theta R}{360}\) = r
r = \(\frac{60 \times 14}{360}\)
= \(\frac{7}{3} = 2\frac{1}{3}\)cm
The area of a square field is 110.25m2. Find the cost of fencing it round at N75.00 per metre
N1,575.00
N3,150.00
N4,734.30
N8,268.75
Correct answer is B
Area = 110.252
f2 = 110.25(square)
l = \(\sqrt{110.25}\) = 10.5m
Since N75.00 per metre
N75.00 = 1 metre; x = 10.5m
x = 787.5 for one side, then four sides = N787.5 x 4
= N3,150.00
2.5cm
3.0cm
3.5cm
4.0cm
Correct answer is D
Distance(d) = d2 = 52 - 32
= 25 - 9
= 16
d = \(\sqrt{16}\)
= 4cm
If 8x-1 = \(\frac{1}{4}\), find x
-\(\frac{-5}{3}\)
-1
-\(\frac{1}{3}\)
\(\frac{1}{3}\)
Correct answer is D
8x-1 = \(\frac{1}{4}\)
23(x - 1 = 2-2
3x - 3 = -2
3x = -2 + 3
3x = 1
x = \(\frac{1}{3}\)
Solve the simultaneous equations x + y = 2 and 3x - 2y = 1
x = 2 and y = 1
x = 1 and y = 1
x = 1 and y = 2
x = -1 and y = 1
Correct answer is B
x + y = 2........... (i)
3x - 2y = 1......(ii)
From (i): x = 2 - y ..........(iii)
subt. (2 - y) for x in (ii)
3(2 - y) 2y = 1
6 - 3y - 2y = 1
-5y = 1 - 6 = -5
y = \(\frac{-5}{-5}\) = 1
subst. (i) for y in (iii)
x = 2 - 1 = 1
x = 1, y = 1