How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
In the diagram above, PQR is a circle centre O. If < QPR is x°, find < QRP.
x°
(90 – x)°
(90 + x)°
(180 – x)°
Correct answer is B
< PQR = 90° (angle in a semi-circle) < QRP = (90 - x)°
In diagram above, QR//TU, < PQR = 80° and < PSU = 95°. Calculate < SUT.
15o
25o
30o
80o
Correct answer is A
< PQR = < PTU = 80°
< TSU = 85°
x = 180° - (80° + 85°)
= 15°
The shaded region above is represented by
the equation
y ≤ 4x + 2
y ≥ 4x + 2
y ≤ -4x + 4
y ≤ 4x + 4
Correct answer is C
Equation of the line
\(\frac{y - 4}{x - 0} = \frac{0 - 4}{1 - 0}\)
\(\frac{y - 4}{x} = \frac{-4}{1}\)
\(\therefore -4x = y - 4\)
\(y = -4x + 4\)
\(\therefore \text{The shaded portion = } y \leq -4x + 4\)
N42,000
N18,000
N16,000
N12,000
Correct answer is C
Angle of sector subtended by yam
= 360o - (70 + 80 + 50)o
= 360o - 200o
= 160o
But \(\frac{80^o}{360^o}\) x T = 8000
T = \(\frac{8000 \times 360^o}{80^o}\)
= N36,000
Hence the amount spent on yam = \(\frac{160^o}{260} \times N36,000\)
= N16,000
y = x + 5
y = -x + 5
y = x - 5
y = -x - 5
Correct answer is B
(x1, y1) = (0,5)
(x2, y2) = (5, 0)
Using \(\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}\)
\(\frac{y - 5}{0 - 5} = \frac{x - 0}{5 - 0}\)
\(\frac{y - 5}{-5} = \frac{x}{5}\)
5(y - 5) = -5x
y - 5 = -x
x + y = 5
y = -x + 5