Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

1,511.

If the simple interest on a sum of money invested at 3% per annum for 2\(\frac{1}{2}\) years is N123, find the principal.

A.

N676.50

B.

N820

C.

N1,640

D.

N4,920

Correct answer is C

I = N123; R = 3%' T = 2\(\frac{1}{2}\) yrs; P = \(\frac{100 \times 1}{RT}\)

P = \(\frac{100 \times 123}{3 \times 2.5}\)

principal(P) = N1640

1,512.

What is the place value of 9 in the number 3.0492?

A.

\(\frac{9}{10000}\)

B.

\(\frac{9}{1000}\)

C.

\(\frac{9}{100}\)

D.

\(\frac{9}{10}\)

Correct answer is B

Place value of 9 in 3.0492

= 0.009

= \(\frac{9}{1000}\)

1,513.

Given that (2x - 1)(x + 5) = 2x2 - mx - 5, what is the value of m

A.

11

B.

5

C.

-9

D.

-10

Correct answer is C

(2x - 1)(x + 5) = 2x2 - mx - 5

2x2 + 10x - x - 5

= 2x2 + 9x - 5 = 2x2 - mx - 5

comparing the co-efficient of x

-m = 9

m = -9

1,514.

What must be added to x2 - 3x to make it a perfect square?

A.

\(\frac{9}{4}\)

B.

\(\frac{9}{2}\)

C.

6

D.

9

Correct answer is A

x2 - 3x + k(perfect square)

k = (-\(\frac{3}{2}\))2 ; k = \(\frac{9}{4}\)

1,515.

\(\begin{array}{c|c} x & 1 & 4 & p \\ \hline y & 0.5 & 1 & 2.5\end{array}\). The table below satisfies the relation y - k\(\sqrt{x}\), where k is a positive constant. Find the value of P,

A.

2

B.

4

C.

10

D.

25

Correct answer is D

From y = \(\frac{1}{2} \sqrt{x}\)

when y = 2.5 or \(\frac{5}{2}\), x = P

\(\frac{5}{2} \times \frac{1}{2} \sqrt{P}\)

\(\sqrt{P} = \frac{10}{2} = 5\)

P = 52

= 25