How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Simplify \(\frac{20}{5\sqrt{28} - 2 \sqrt{63}}\)
\(\frac{5\sqrt{7}}{7}\)
\(\frac{5\sqrt{5}}{7}\)
\(\frac{7\sqrt{5}}{7}\)
\(\frac{7\sqrt{7}}{5}\)
Correct answer is A
\(\frac{20}{5 \sqrt{4 \times 7} - 2\sqrt{9 \times 7}}\)
\(\frac{20}{10 \sqrt{7} - 6\sqrt{7}}\)
= \(\frac{20 \sqrt{7}}{4 \sqrt{7}}\)
= \(\frac{5\sqrt{7}}{7}\)
-6oC
-4oC
4oC
8oC
Correct answer is B
Temperature = -5oC
It fell by 6oC = -5oC - 6oC
= -11oC
Then rose by 7oC = -11 + 7
= -4oC (final temperature)
Which of the following is not a measure of centre tendency?
mean
mode
range
median
Correct answer is C
No explanation has been provided for this answer.
30m2
57m2
120m2
225m2
Correct answer is C
Area of carpet = 2.5 x 2.4 = 6
Let F represent the floor
6 = 5% of F
6 = \(\frac{5}{100}\) x F
5F = 6 x 100
F = 6 x \(\frac{100}{5}\)
= 120m2
The values of three angles at a point are 3y - 45o, y + 25o and yo . Find the value of y.
40o
58o
68o
76o
Correct answer is D
(3y - 450 + (y + 25) + t = 360o(angles at a point)
3y - 45 + y + 25 + y = 360
5y = 360 + 20
5y = 380
y = \(\frac{380}{5}\)
= 76o