How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
{1, 3, 5, 7, 9}
[2, 4, 6, 8, 10}
\(\varnothing\)
{1, 2, 6, 8, 10}
Correct answer is C
P1 = {2, 4, 6, 8, 10}; {1, 3, 5, 7, 9}
P1 \(\cap\) q1 = {} or \(\varnothing\)
140m
220m
280m
440m
Correct answer is D
radius = \(\frac{diameter}{2}\) = \(\frac{1.4}{2}\)
= 0.7m
circumference = 2\(\pi r = 2 \times \frac{22}{7} \times 0.7m = 4.4m\)
distance covered = 4.4m x 100 = 440m
1:4
1:5
3:4
4:5
Correct answer is D
(1 - \(\frac{20}{100}\)) = cash payment fraction= \(\frac{4}{5}\)
The ratio of the cash payment to the marked price = 4:5
If p = [\(\frac{Q(R - T)}{15}\)]\(^ \frac{1}{3}\), make T the subject of the relation
T = R + \(\frac{P^3}{15Q}\)
T = R - \(\frac{15P^3}{Q}\)
T = R + \(\frac{P^3}{15Q}\)
T = 15R - \(\frac{Q}{P^3}\)
Correct answer is B
Cubic both sides; P3 = \(\frac{Q(R - T)}{15}\)
(cross multiplication) Q(R - T) = 15P3
(divide both sides by Q); R - T = 15\(\frac{1}{Q}\)
(subtract r from both sides) - T = \(\frac{15P^3}{Q - R}\)
T = R - \(\frac{15P^3}{Q}\)
22cm2
44cm3
77cm3
3082
Correct answer is C
Volume = \(\frac{1}{3} \pi r^2h = \frac{1}{3} \times \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times \frac{6}{1}\)
V = \(\frac{6468}{84}\)
= 77cm3