How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
y = (x - 3)3
y = (x + 3)3
y = x3 - 27
y = -x3 + 27
Correct answer is C
y = x3 - 27, y = -27 \(\to\) (0, -27)
when y = 0, x = 3 (3, 0)
The bar chart shows the distribution of marks in a class test. How many students took the test?
15
20
25
30
Correct answer is B
Number f students that took the test = \(\sum f\). Where f is the frequencies
= 2 + 5 + 0 + 3 + 4 + 0 + 0 + 2 + 3 + 1 + 2 = 20
From the figure, calculate TH in centimeters
\(\frac{5}{\sqrt{3} + 1}\)
\(\frac{5}{\sqrt{3} - 1}\)
\(\frac{5}{\sqrt{3}}\)
\(\frac{\sqrt{3}}{5}\)
Correct answer is B
TH = tan 45o, TH = QH
\(\frac{TH}{5 + QH}\) = tan 30o
TH = (b + QH) tan 30o
QH = 56 (5 + QH) \(\frac{1}{\sqrt{3}}\)
QH(1 - \(\frac{1}{\sqrt{3}}\)) = \(\frac{5}{\sqrt{3}}\)
QH = \(\frac{5\sqrt{3}}{\sqrt{3}} - \frac{1}{\sqrt{3}}\)
= \(\frac{5}{\sqrt{3} - 1}\)
6cm
7cm
8cm
9cm
Correct answer is C
Since area of square PQRS = 100cm2
each lenght = 10cm
Also TUYS : XQVU = 1 : 16
lengths are in ratio 1 : 4, hence TU : UV = 1: 4
Let TU = x
UV = 1: 4
hence TV = x + 4x = 5x = 10cm
x = 2cm
TU = 2cm
UV = 8cm
But TU = SY and UV = YR
YR = 8cm
7 \(\sqrt{3}\)cm
12.9cm
\(\sqrt{87}\)cm
7cm
Correct answer is B
SQ2 + OS2 = OQ2 + 52 = 142
SQ2 = 142 - 52
196 - 25 = 171
ST2 + TQ2 = SQ2
ST2 + 22 = 171
ST2 = 171 - 4
= 167
ST = \(\sqrt{167}\)
= 12.92 = 12.9cm