How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Determine the value of x in the figure
134o
81o
53o
46o
Correct answer is A
Within the triangle,
180° - (81° + 53°) = 46°
In a cyclic quadrilateral, the sum of two opposite angles = 180°
\(\therefore\) x = 180° - 46° = 134°
Use the graph of the curve y = f(x)to solve the inequality f(x) \(\leq\) 0
-1 \(\geq\) x \(\geq\) 1, x \(\geq\) 2
x \(\leq\) -1, 1 \(\geq\) x \(\geq\) 2
x \(\geq\) -1, 1 \(\geq\) x \(\geq\) 2
x \(\geq\) 2, -1 \(\geq\) x \(\geq\) 1
Correct answer is B
-1 \(\geq\) x \(\geq\) 1, 1 < x \(\geq\) 2
Combining solutions
= x \(\leq\) 1; 1 \(\geq\) x \(\geq\) 2
52.0
43.2
40.0
12.0
Correct answer is D
No explanation has been provided for this answer.
The equation of the line in the graph is
3y = 4x + 12
3y = 3x + 12
3y = -4x + 12
3y = -4x + 9
Correct answer is C
Gradient of line = \(\frac{\text{Change in y}}{\text{Change in x}} = \frac{y_2 - y_1}{x_2 - x_1}\)
y2 = 0, y1 = 4
x2 = 3 and x1 = 0
\(\frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 4}{3 - 0} = \frac{-4}{3}\)
Equation of straight line = y = mx + c
where m = gradient and c = y
intercept = 4
y = 4x + \(\frac{4}{3}\), multiple through by 3
3y = 4x + 12
2h
2\(\pi\)h
\(\pi\)h
\(\frac{\pi h}{2}\)
Correct answer is A
\(\frac{x}{r}\) = \(\frac{x + h}{2r}\)
2 x r = r (x + h)
Total height of cone = x + h
but x = h
total height = 2h