Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

1,576.

the shaded portion in the graph is represented by

A.

y + x - x \(\leq\) 0, y - x \(\leq\) 0

B.

y - x + x, 3 \(\leq\) 0, y - x \(\geq\) 0

C.

y + x - 3 \(\geq\) 0, y + x \(\leq\) 0

D.

y - x + x3 \(\geq\) 0, y + x \(\leq\) 0

Correct answer is C

No explanation has been provided for this answer.

1,577.

The bar chart shows the distribution of marks scored by 60 pupils in a test in which the maximum score was 10. If the pass mark was 5, what percentage of the pupils failed the test?

A.

59.4%

B.

50.0%

C.

41.7%

D.

25.0%

Correct answer is C

\(\begin{array}{c|c} x & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 \\ \hline f & 1 & 9 & 4 & 7 & 10 & 8 & 7 & 9 & 8 & 2 & 1\end{array}\)
no pupils who failed the test = 1 + 3 + 4 + 7 + 10

= 25

5 of pupils who fail = \(\frac{25}{60}\) x 100%

= 41.70%

1,578.

The pie chart shows the monthly expenditure pf a public servant. The monthly expenditure on housing is twice that of school fees. How much does the worker spend on housing if his monthly income is N7200?

A.

N1000

B.

N2000

C.

N3000

D.

N4000

Correct answer is B

Let the monthly expenditure on school fees be x let the monthly expenditure on housing be 2x; angle of housing and school fee in a pie chart = 360o - (120o + 90o)

= 360o - 210o = 150o

Angle of housing in a pie-chart = \(\frac{2}{3}\) x 150 = 100

\(\frac{100}{360}\) x 7200 = N2,000

1,579.

A chord of a circle radius \(\sqrt{3cm}\) subtends an angle of 60° on the circumference of he circle. Find the length of the chord

A.

\(\frac{\sqrt{3}}{2}\)

B.

\(\frac{3}{2}\)

C.

3

D.

\(\sqrt{3}\)cm

Correct answer is D

Length of chord = \(2r \times \sin(\frac{\theta}{2})\)

= \( 2 \times \sqrt{3} \times \sin(\frac{60}{2})\)

= \(2 \times \sqrt{3} \times \frac{1}{2}\)

= \(\sqrt{3}\) cm.

1,580.

In the diagram, QTR is a straight line and < PQT = 30o. find the sin of < PTR

A.

\(\frac{8}{15}\)

B.

\(\frac{2}{3}\)

C.

\(\frac{3}{4}\)

D.

\(\frac{15}{16}\)

Correct answer is C

\(\frac{10}{\sin 30^o} = \frac{15}{\sin x} = \frac{10}{0.5} = \frac{15}{\sin x}\)

\(\frac{15}{20} = \sin x\)

sin x = \(\frac{15}{20} = \frac{3}{4}\)

N.B x = < PRQ