How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
17.5 - 20.5
16.5 - 19.5
15.5 - 19.5
15.5 - 18.5
Correct answer is A
No explanation has been provided for this answer.
If the diagram is the graph of y = x2, the shaded area is
64 square units
\(\frac{126}{4}\) square units
32 square units
\(\frac{64}{3}\) square units
Correct answer is D
A = \(\int^{x = 4}_{x = 0}\) ydx = \(\int^{4}_{0}\) x2dx = [\(\frac{x^3}{3} + c]^{4}_{0}\)
= \(\frac{64}{3}\) square units
32cm
26cm
20cm
16cm
Correct answer is B
\(\bigtriangleup\)OEN = \(\bigtriangleup\)OGN
OE = OG = r(radii)
(r - 8)2 + 122 = r2
r2 - 16r + 64 + 144 = r2
16r = 64 + 144 = r2
16r = 64 + 144 = 208
\(\frac{208}{16}\) = 13cm
FH = 2FO = 2OH = 2R
= 2 x 13cm
= 26cm
In the diagram, If < RPS = 50o, < RPQ = 30o and pq = QR, Find the value of < prs
50o
60o
70o
80o
Correct answer is C
< QPR = < PRQ = 30o (PQ = QR)
< SPQ + < QRS = 180o (supplementary)
80 + < QRS = 180o = < QRS = 180o - 80o = 100o
< QRP + < PRS = 100o = 30o + < PRS = 100o
= < PRS = 100o - 30o = 70o
7
8
9
12
Correct answer is A
degree of excellent in the pie-chart = 360o - (90o + 120o + 80o) = 360o - 290o = 70o
= 360o = 36 students
70 = \(\frac{70^o}{360^o}\) x 36 = 7