Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

1,811.

Write the decimal number 39 to base 2

A.

10011 base 2

B.

110111 base 2

C.

111001 base 2

D.

100101 base 2

E.

19.5 base 2

Correct answer is A

\(\begin{array}{c|c} 2 & 39\\ 2 & 19 R 1\\ 2 & 9 R 1\\2 & 4 R 0\\2 & 1 R 0\\ 2 & 1 R 1\end{array}\)

= 10011 base 2

1,812.

If x varies inversely as y, and y varies directly as the square root of z, and z varies directly \(\frac{1}{w^2}\) write down in words how x varies with w

A.

x varies inversely as w2

B.

x varies directly as w2

C.

x varies directly as w

D.

x varies inversely as w

E.

x varies directly as square root of w

Correct answer is B

No explanation has been provided for this answer.

1,813.

A cylindrical motor of height 12cm has uniform thickness of 2cm. If the diameter of its outer cross section is 10cm, Find the volume of the constituent material. (take \(\pi\) = \(\frac{22}{7}\)

A.

\(\frac{6600}{7}\)cm3

B.

270cm3

C.

660cm3

D.

\(\frac{4224}{7}\)cm3

E.

\(\frac{1980}{7}\)cm3

Correct answer is D

V = \(\pi\)r2h

= \(\frac{22}{7}\) x 52 x 12 - \(\frac{22}{7}\) x 32 x 12

= \(\frac{22}{7}\) x 12(52 - 32)

= \(\frac{4224}{7}\)

1,814.

If a function is defined by f(x + 1) = 3x2 - x + 4, Find f(0).

A.

4

B.

6

C.

9

D.

8

E.

2

Correct answer is D

f(x + 1) = 3x2 - x + 4

f(0) = f(x + 1)

x + 1 = 0 ===> x = -1

f(0) = 3(-1)2 - (-1) + 4

f(0) = 3 + 1 + 4

= 8

1,815.

The expression x\(^3\) - 4x\(^2\) + cx + d is such that x + 1 is its factor, and its value is 1 when x is -2. Find c and d.

A.

c = 4 and d = -9

B.

c = -4 and d = 9

C.

c = -20 and d = -15

D.

c = 20 and d = -15

E.

c = -20 and d = 15

Correct answer is C

F(X) = x\(^3\) - 4x\(^2\) + cx + d

= (X + 1) Q(X) + R

x = -1, R = 0,f(-1) = -1\(^3\) - 4(-1)\(^2\) + c(-1) + d = 0

-1 - 4 - c + d = 0

d - c = 5................(i)

f(-2) = -2\(^3\) - 4(-2)\(^2\) + c(-2) + d = 1

= -8 - 16 - 2c + d

= 1

-8 - 16 - 2c + d = 1

-24 - 2c + d = 1

d - 2c = 1 + 24

d - 2c = 25.................(ii)

\(\frac{d - c = 5}{-c = 20}\) d - c = 5

c = -20

d - (-20) = 5

d + 20 = 5

d = 5 - 20

= -15

c = -20, d = -15