How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
72
100
90
200
125
Correct answer is D
P \(\alpha\) \(\frac{q^2}{r}\)
P = \(\frac{kq^2}{r}\)
k = \(\frac{pr}{q^2}\)
= \(\frac{36 x 4}{(3)^2}\)
p = \(\frac{16q^2}{r}\)
= \(\frac{16 \times 25}{2}\)
= 200
Simplify \(\frac{3^n - 3^{n - 1}}{3^3 \times 3^n - 27 \times 3^{n - 1}}\)
1
6
\(\frac{1}{27}\)
\(\frac{4}{3}\)
Correct answer is C
\(\frac{3^n - 3^{n - 1}}{3^3 \times 3^n - 27 \times 3^{n - 1}}\) = \(\frac{3^n - 3^{n - 1}}{3^3(3^n - 3^{n - 1})}\)
= \(\frac{3^n - 3^{n - 1}}{27(3^n - 3^{n - 1})}\)
= \(\frac{1}{27}\)
Rationalize \(\frac{5\sqrt{7} - 7\sqrt{5}}{\sqrt{7} - \sqrt{5}}\)
-2\(\sqrt{35}\)
4\(\sqrt{7}\) - 6\(\sqrt{5}\)
-\(\sqrt{35}\)
4\(\sqrt{7}\) - 8\(\sqrt{5}\)
\(\sqrt{35}\)
Correct answer is C
\(\frac{5\sqrt{7} - 7\sqrt{5}}{\sqrt{7} - \sqrt{5}}\) = \(\frac{5\sqrt{7} - 7\sqrt{5}}{\sqrt{7} - \sqrt{5}}\) x \(\frac{\sqrt{7} + \sqrt{5}}{\sqrt{7} + \sqrt{5}}\)
= \(\frac{(5 \times 7) + (5 \sqrt{7} \times 5) - (7 \times \sqrt{5} \times 7) (-7 \times 5)}{(\sqrt{7})^2}\)
= \(\frac{5 \sqrt{35} - 7\sqrt{35}}{2}\)
= \(\frac{-2\sqrt{35}}{2}\)
= - \(\sqrt{35}\)
1035
10305
1025
20025
30325
Correct answer is B
Total cost of 1035 oranges at N145 each
= 1035 x 145
= 20025
Total selling price at N245 each
= (103)5 x 245
= 30325
Hence his gain = 30325 - 20025
= 10305
-3 = \(\frac{y + 4}{x + 1}\)
4y = -3 + x
\(\frac{y}{x}\) = \(\frac{-3}{4}\)
4x = y + 3
Correct answer is D
P(x, y), P(0, 3) If x increases by 1 unit and y by 4 units, then ratio of x : y = 1 : 4
\(\frac{x}{1}\) = \(\frac{y}{4}\)
y = 4x
Hence the sign of the graph is y + 3 = 4x