How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
\(\frac{4}{\sqrt{3}}\)
\(4 \sqrt{3}\)
\(\sqrt{\frac{3}{2}}\)
\(\frac{1}{\sqrt{3}}\)
\(\frac{2}{\sqrt{3}}\)
Correct answer is A
\(\frac{\cot (90 - \theta)}{sin^2\theta}\)
\(\cot (90 - \theta) = \tan \theta\)
\(\therefore \frac{\cot (90 - \theta)}{\sin^{2} \theta} = \frac{\tan \theta}{\sin^{2} \theta}\)
\(\tan \theta = \frac{\sqrt{3}}{3}\)
\(\sin \theta = \frac{1}{2} \implies \sin^{2} \theta = \frac{1}{4}\)
\(\frac{\cot(90 - \theta)}{\sin^{2} \theta} = \frac{\sqrt{3}}{3}\div\frac{1}{4}\)
= \(\frac{4}{\sqrt{3}}\)
Find the area of a regular hexagon inscribed in a circle of radius 8cm
16\(\sqrt{3}\) cm3
96\(\sqrt{3}\) cm3
192\(\sqrt{3}\) cm3
16\(\sqrt{3}\) cm2
33cm2
Correct answer is B
Area of a regular hexagon = 8 x 8 x sin 60o
= 32 x \(\frac{\sqrt{3}}{2}\)
Area = 16\(\sqrt{3}\) x 6 = 96 \(\sqrt{3}\)cm2
\(\frac{7}{10}\)
\(\frac{3}{5}\)
\(\frac{4}{5}\)
\(\frac{3}{10}\)
Correct answer is B
Simple Space: (1, 2, 3, 4, 5, 6, 7, 8, 9, 10 = 10)
Prime: (2, 3, 5, 7)
multiples of 3: (3, 6, 9)
Prime or multiples of 3: (2, 3, 5, 6, 7, 9 = 6)
Probability = \(\frac{6}{10}\)
= \(\frac{3}{5}\)
Without using table, calculate the value of 1 + sec2 30o
2\(\frac{1}{3}\)
\(\frac{2}{15}\)
\(\frac{5}{3}\)
3\(\frac{1}{2}\)
Correct answer is A
1 + sec2 30o = sec 30o
= \(\frac{2}{\sqrt{3}}\)
\(\frac{(2)^2}{3}\)
= \(\frac{4}{3}\)
1 + sec2 30o = sec 30o
= 1 + \(\frac{4}{3}\)
= 2\(\frac{1}{3}\)
S 18o W
S 72o W
S 72o E
S 27o E
S 27o W
Correct answer is B
B = Bird ; H = Hunter.
Bearing of the hunter from the bird = S 72° W.