Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

2,121.

A train moves from P to Q at an average speed of 90km/h and immediately returns from Q to P through the same route at an average speed of 45km/h. Find the average speed for the entire journey

A.

55.00km/h

B.

60.00km/h

C.

67.50km\h

D.

75.00km\h

Correct answer is C

Average speed from P to Q = 90km\h

Average speed from O to P = 45km/h

Average for the entire journey = 90 + 45

\(\frac{135}{2}\) = 67.50 km/h

2,122.

Reduce each number to two significant figures and then evaluate \(\frac{0.021741 \times 1.2047}{0.023789}\)

A.

0.8

B.

0.9

C.

1.1

D.

1.2

Correct answer is C

\(\frac{0.021741 \times 1.2047}{0.023789}\) = \(\frac{0.022 \times 1.2}{0.024}\) (to 216)

= \(\frac{0.0264}{0.024}\)

= 1.1

2,123.

A rectangular lawn has an area of 1815 square yards. if its length is 50 meters, find its width in meters given that 1 metre equals 1.1 yards

A.

39.93

B.

35.00

C.

33.00

D.

30.00

Correct answer is D

1m = 1.1 yard, length(L)= 50m

= (50 x 1.1)yards

= 55 yards

Area(A) = length(L) y width (W)

1815 = 55y width (W)

width (w) = \(\frac{1815}{55}\)

= 33 yards

But 33 yards = 30 meters

2,124.

Find the least length of a rod which can be cut into exactly equal strips, each of either 40cm or 48cm in length

A.

120cm

B.

240cm

C.

360cm

D.

480cm

Correct answer is B

The least length is \(\frac{40}{48}\) = \(\frac{5}{8}\)

for the rod to be cut in exactly equal trips

Ratio \(\frac{5}{6}\) : \(\frac{48}{40}\)

\(\frac{\frac{5}{6}}{\frac{40}{48}}\) = 1

\(\frac{5}{6}\) x \(\frac{48}{40}\) = \(\frac{240}{240}\) = 1

The least length = 240cm

2,125.

Convert 241 in base 5 to base 8,

A.

718

B.

1078

C.

1768

D.

2418

Correct answer is B

2415 = 2 x 52 + 4 x 5 + 1 x 5 + 1 x 5o

50 + 20 + 1 = 7110

Convert 7110 to base 8
\(\begin{array}{c|c} 8 & 71 \\ 8 & 8 R 7\\8 & 1 R 0\\8 & 0 R 1\end{array}\)

= 1078