How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
80
270
120
90
Correct answer is D
Total angles = 360°
100 + 60 + 80 + M = 360
M = 360 - 240 = 120
Orange (M) = 120° and F ( fruits in total)
For Apples:
\(\frac{80}{360} \times F\) = 60
F = \(\frac{60 \times 360}{80}\)
F = 270 fruits in total
For Orange
= \(\frac{120}{360} \times 270\)
= 90 oranges
18 ≤ d ≤ 23
18 < d < 23
18 ≤ d < 23
18 < d ≤ 23
Correct answer is D
distance d more than 18 KM = d > 18 0r 18 < d distance d but not more than 23 KM = d ≤ 23 Mathematically; 18 < d ≤ 23
325
235
175
400
Correct answer is A
A for Adults
C for children
a + c = 500
c = 500 - a
4.5a + 3c = 1987.50
where c = 500 - a
4.5a + 3(500 - a) = 1987.50
4.5a - 3a = 1987.50 - 1500
1.5a = 487.5
a = 487.5 / 1.5
a = 325 tickets
c = 500 - a
c = 500 - 325
c = 175 tickets
Check:
from 4.5a + 3c
4.5 (325) = 1,462.5
+
3(175) = 525
(-6,-2)
(0,8)
(4,10)
(0,4)
Correct answer is B
The formula for midpoint = \(\frac{x_1 + x_2}{2}\), \(\frac{y_1 + y_2}{2}\)
(-4,-2) = (x,y)
x = \(\frac{x_1 + x_2}{2}\)
-4 = \(\frac{-8 + p}{2}\)
-4 * 2 = -8 + p
-8 + 8 = p
: p = 0
y = \(\frac{y_1 + y_2}{2}\)
-2 = \(\frac{-12 + q}{2}\)
-2 * 2 = -12 + q
-4 + 12 = q
: q = 8
| Height(cm) | 160 | 161 | 162 | 163 | 164 |
165 |
| No. of players | 4 | 6 | 3 | 7 | 8 | 9 |
the table shows the height of 37 players of a basketball team calculates correct to one decimal place the mean height of the players.
163.0
162.0
160.0
165.0
Correct answer is A
∑fx = (160 * 4) + (161 * 6) + (162 * 3) + (163 * 7) + (164 * 8) + (165 * 9)
=640 + 966 + 486 + 1,141 + 1,312 + 1,485
= 6,030
∑f = 4 + 6 + 3 + 7 + 8 + 9
= 37
= \(\frac{∑fx}{∑f}\)
= \(\frac{6030}{37}\)
= 162.97 or 163