How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
130°
115°
58°
68°
Correct answer is C
Alternate segments are equal : R° = 64°
An isosceles triangle has two angles ( Q° & N° ) equal as A°
R° + A° + A° = 180°
2A°= 180 - 64
2A° = 116°
A = \(\frac{116}{2}\)
A = 58.
: Q° = 58, N° = 58 and T° = 58
As Alternate segments are equal: T = Q
215°
70°
135°
145°
Correct answer is A
sum of angle in a straight line = 180°
35 + m = 180
m = 180 - 35 = 145°
Corresponding angles are congruent i.e equal to each other
Angle X and M are congruent = 145
sum of angle in a straight line = 180°
110 + n = 180
m = 180 - 110 = 70°
Angle Y and N are congruent = 70°
∴∴ ( x + y) = ( 145 + 70)°
(x + y) = 215°
3.71
3.70
3.69
3.72
Correct answer is A
The mean = sum of 1\(\frac{1}{2}\), 2\(\frac{2}{3}\), 3\(\frac{3}{4}\), 4\(\frac{4}{5}\), and 5\(\frac{5}{6}\) divided by their quantity.
Mean = ( 1\(\frac{1}{2}\) + 2\(\frac{2}{3}\) + 3\(\frac{3}{4}\) + 4\(\frac{4}{5}\) + and 5\(\frac{5}{6}\) ) / 5
= 3.708 or 3.71( 2 d.p )
84cm\(^2\)
80cm\(^2\)
30cm\(^2\)
94cm\(^2\)
Correct answer is B
Area of circle = πr\(^2\) = \(\frac{22}{7}\) * 7\(^2\) = 154cm\(^2\)
Area o Trapezium = \(\frac{(a + b) h}{2}\) = \(\frac{(10 + 21)8}{2}\) = 124cm\(^2\)
Area of the region not covered = Area of (Circle - Trapezium)
= 154 - 124
= 30cm\(^2\)
In the diagram, O is the centre of the circle PQRS, ∠PQR = 72° and OR is parallel to PS. Find ∠ OPS.
18°
108°
54°
36°
Correct answer is D
Angle at the centre O is twice the angle at the circumference.
i.e O = 72° * 2 = 144°
∠OPS = 180 - 144 = 36°