How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
2, 1
1, 2
1, 5
5, 2
Correct answer is C
Mean \(\bar{x}\) = \(\frac{\sum fx}{\sum f}\)
= \(\frac{5.2}{1}\)
= \(\frac{8 + 4y + 36 + 40}{4 + y + 6 + 5}\)
= \(\frac{5.2}{1}\)
= \(\frac{84 + 4y}{15 + y}\)
= 5.2(15 + y)
= 84 + 4y
= 5.2 x 15 + 5.2y
= 84 + 4y
= 78 + 5.2y
= 84 = 4y
= 5.2y - 4y
= 84 - 78
1.2y = 6
y = \(\frac{6}{1.2}\)
= \(\frac{60}{12}\)
= 5
216o
108o
68o
62o
Correct answer is D
H will represent \(\frac{108}{630}\) x \(\frac{360^o}{1}\) ≈ 62°
Evaluate the integral \(\int^{\frac{\pi}{4}}_{\frac{\pi}{12}} 2 \cos 2x \mathrm {d} x\)
-\(\frac{1}{2}\)
-1
\(\frac{1}{2}\)
1
Correct answer is C
\(\int_{\frac{\pi}{12}} ^{\frac{\pi}{4}} 2 \cos 2x \mathrm {d} x\)
= \([\frac{2 \sin 2x}{2}]|_{\frac{\pi}{12}} ^{\frac{\pi}{4}}\)
= \(\sin 2x |_{\frac{\pi}{12}} ^{\frac{\pi}{4}}\)
= \(\sin 2(\frac{\pi}{4}) - \sin 2(\frac{\pi}{12})\)
= \(\sin \frac{\pi}{2} - \sin \frac{\pi}{6}\)
= \(1 - \frac{1}{2} = \frac{1}{2}\)
37.00\(\pi\)
37.33\(\pi\)
40.00\(\pi\)
42.67\(\pi\)
Correct answer is B
\(\frac{dv}{dt}\) = \(\pi\)(20 - t2)cm2S-1
\(\int\)dv = \(\pi\)(20 - t2)dt
V = \(\pi\) \(\int\)(20 - t2)dt
V = \(\pi\)(20 \(\frac{t}{3}\) - t3) + c
when c = 0, V = (20t - \(\frac{t^3}{3}\))
after t = 2 seconds
V = \(\pi\)(40 - \(\frac{8}{3}\)
= \(\pi\)\(\frac{120 - 8}{3}\)
= \(\frac{112}{3}\)
= 37.33\(\pi\)
Obtain a maximum value of the function f(x) x3 - 12x + 11
-5
-2
2
27
Correct answer is D
f(x) = x3 - 12x + 11
\(\frac{df(x)}{dx)}\) = 3x2 - 12 = 0
∴ 3x2 - 12 = 0 \(\to\) x2m = 4
x = \(\pm\)2, f(+2) = 8 - 24 + 11 = -15
= f(-2) = (-8) + 24 + 11
= 35 - 8 = 27
∴ maximum value = 27