How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
x2468f4y65
If the mean of the above frequency distribution is 5.2, find y
2, 1
1, 2
1, 5
5, 2
Correct answer is C
Mean ˉx = ∑fx∑f
= 5.21
= 8+4y+36+404+y+6+5
= 5.21
= 84+4y15+y
= 5.2(15 + y)
= 84 + 4y
= 5.2 x 15 + 5.2y
= 84 + 4y
= 78 + 5.2y
= 84 = 4y
= 5.2y - 4y
= 84 - 78
1.2y = 6
y = 61.2
= 6012
= 5
216o
108o
68o
62o
Correct answer is D
H will represent 108630 x 360o1 ≈ 62°
Evaluate the integral ∫π4π122cos2xdx
-12
-1
12
1
Correct answer is C
∫π4π122cos2xdx
= [2sin2x2]|π4π12
= sin2x|π4π12
= sin2(π4)−sin2(π12)
= sinπ2−sinπ6
= 1−12=12
37.00π
37.33π
40.00π
42.67π
Correct answer is B
dvdt = π(20 - t2)cm2S-1
∫dv = π(20 - t2)dt
V = π ∫(20 - t2)dt
V = π(20 t3 - t3) + c
when c = 0, V = (20t - t33)
after t = 2 seconds
V = π(40 - 83
= π120−83
= 1123
= 37.33π
Obtain a maximum value of the function f(x) x3 - 12x + 11
-5
-2
2
27
Correct answer is D
f(x) = x3 - 12x + 11
df(x)dx) = 3x2 - 12 = 0
∴ 3x2 - 12 = 0 → x2m = 4
x = ±2, f(+2) = 8 - 24 + 11 = -15
= f(-2) = (-8) + 24 + 11
= 35 - 8 = 27
∴ maximum value = 27