How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
What is the perpendicular distance of a point (2, 3) from the line 2x - 4y + 3 = 0?
√52
√520
5√13
6
Correct answer is A
2x - 4y + 3 = 0
Required distance = (2×2)+3(−4)+3√22+(−4)2
= 4−12+3√20
= −5−2√5
= √52
If the distance XZ is 12Km. Calculate the bearing of Z from X
240o
210o
150o
60o
Correct answer is B
Using sinØ = 6√312 → √32
sinØ = √32 or 60°
The bearing of Z from X = [270 - 60]° → 210°
If in the diagram, FG is parallel to KM, find the value of x
75o
95o
105o
125o
Correct answer is B
No explanation has been provided for this answer.
800π9km
800√3π9km
800π km
800√3π km
Correct answer is C
Angular difference (θ)= 25° + 20° = 45°
α = common latitude = 60°
S = \frac{\theta}{360°} \times 2\pi R \cos \alpha
S = \frac{45°}{360°} \times 2 \pi \times 6400 \times \cos 60°
= \frac{6400\pi}{8} = 800\pi km
If the angles of quadrilateral are (p + 10)°, (2p - 30)°, (3p + 20)° and 4p°, find p.
63
40
36
28
Correct answer is C
The sum of angles in a quadrilateral = 360°
\therefore (p + 10) + (2p - 30) + (3p + 20) + 4p = 360
10p = 360° \implies p = \frac{360}{10} = 36°