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Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

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2,316.

Make t the subject of formula S = ut + $\frac{1}{2} at^2$

$\frac{1}{a}$ (-u + $\sqrt{U^2 - 2as}$ )

$\frac{1}{a}$ {u $\pm$ (U² - 2as)}

$\frac{1}{a}$ {u $\pm$ $\sqrt{2as}$ }

$\frac{1}{a}$ {-u + $\sqrt{( 2as)}$ }

View answer & explanation

Correct answer is A

Given S = ut + $\frac{1}{2} at^2$

S = ut + $\frac{1}{2} at^2$

∴ 2S = 2ut + at²

= at² + 2ut - 2s = 0

t = $\frac{-2u \pm 4u^2 + 2as}{2a}$

= -2u $\pi$ $\frac{\sqrt{u^2 4u^2 + 2as}}{2a}$

= $\frac{1}{a}$ (-u + $\sqrt{U^2 - 2as}$ )

2,317.

Solve the equation: $y - 11\sqrt{y} + 24 = 0$

8, 3

64, 9

6, 4

9, -8

View answer & explanation

Correct answer is B

$y - 11\sqrt{y} + 24 = 0 \implies y + 24 = 11\sqrt{y}$

Squaring both sides,

$y^{2} + 48y + 576 = 121y$

$y^{2} + 48y - 121y + 576 = 0 \implies y^{2} - 73y + 576 = 0$

$y^{2} - 64y - 9y + 576 = 0$

$y(y - 64) - 9(y - 64) = 0$

$(y - 9)(y - 64) = 0$

$\therefore \text{y = 64 or y = 9}$

2,318.

Factorize $9p^2 - q^2 + 6qr - 9r^2$

(3p - 3q + r)(3p - q - 3r)

(6p - 3q - 3r)(3p - q - 4r)

(3p - q + 3r)(3p + q - 3r)

(3q - p + 3r)(3q - p + 3r)

View answer & explanation

Correct answer is C

$9p^{2} - q^{2} + 6qr - 9r^{2}$

= $9p^{2} - (q^{2} - 6qr + 9r^{2})$

= $9p^{2} - (q^{2} - 3qr - 3qr + 9r^{2})$

= $9p^{2} - (q(q - 3r) - 3r(q - 3r))$

= $9p^{2} - (q - 3r)^{2}$

= $(3p + (q - 3r))(3p - (q - 3r))$

= $(3p + q - 3r)(3p - q + 3r)$

2,319.

If U = (1, 2, 3, 6, 7, 8, 9, 10) is the universal set. E = (10, 4, 6, 8, 10) and F = {x: 1x $^{2}$ = 2\(^{6}, x is odd}. Find (E ∩ F)', where ' means the complement of a set.

(0)

(8)

$\phi$

View answer & explanation

Correct answer is D

U = (1, 2, 3, 6, 7, 8, 9, 10)

E = (10, 4, 6, 8, 10)

F = (x : x $^2$ = 2 $^6$ , x is odd)

∴ F = $\phi$ Since x $^2$ = 2 $^6$ = 64

x = $\pm 8$ which is even

∴ E ∩ F = $\phi$ Since there are no common elements