1a (-u + √U2−2as)
1a {u ± (U2 - 2as)}
1a {u ± √2as}
1a {-u + √(2as)}
Correct answer is A
Given S = ut + 12at2
S = ut + 12at2
∴ 2S = 2ut + at2
= at2 + 2ut - 2s = 0
t = −2u±4u2+2as2a
= -2u π √u24u2+2as2a
= 1a (-u + √U2−2as)
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