How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
\(P = \frac{Q}{12R}\)
\(P = \frac{12Q}{R}\)
\(P = 12QR\)
\(P = \frac{12}{QR}\)
Correct answer is B
\(P \propto \frac{Q}{R}\)
\(P = K \frac{Q}{R}\)
When Q = 36, R = 16, P = 27
Then substitute into the equation
\(27 = K \frac{36}{16}\)
\(K = \frac{27 \times 16}{36}\)
\(K = 12\)
So the equation connecting P, Q and R is
\(P = \frac{12Q}{R}\)
y varies directly as w2. When y = 8, w = 2. Find y when w = 3
18
12
9
6
Correct answer is A
\(y \propto w^2\)
y = kw2
8 = k(2)2
8 = k(4)
k = 8/4
k = 2
Thus y = 2w2
When w = 3, y = 2(3)2
y = 2 x 9 = 18
Find the value of k if y - 1 is a factor of y3 + 4y2 + ky - 6
-6
-4
0
1
Correct answer is D
if y - 1 is a factor of y3 + 4y2 + ky - 6, then
f(1) = (1)3 + 4(1)2 + k(1) - 6 = 0 (factor theorem)
1 + 4 + k - 6 = 0
5 - 6 + k = 0
-1 + k = 0
k = 1
(2y - 3x) (y + 6x)
(2y - 3x) (y - 6x)
(2y + 3x) (y - 6x)
(3y + 2x) (y - 6x)
Correct answer is B
2y2 - 15xy + 18x2
2y2 - 12xy - 3xy + 18x2
2y(y - 6x) - 3x(y - 6x)
(2y - 3x) (y - 6x)
If gt2 - k - w = 0, make g the subject of the formula
\(\frac{k + w}{t^2}\)
\(\frac{k - w}{t^2}\)
\(\frac{k + w}{t}\)
\(\frac{k - w}{t}\)
Correct answer is A
gt2 - k - w = 0
gt2 = k + w
\(g = \frac{k + w}{t^2}\)