How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
the perpendicular bisector of the line segment X Y
a line parallel to the line segment XY
a circle with XY as diameter
the line perpendicular to the line segment XY
Correct answer is A
No explanation has been provided for this answer.
Which of the following quadratic equations has \(-\frac{1}{2}\) and \(\frac{3}{4}\) as its roots?
8x2 + 11x - 3 = 0
8x2 -11x – 3 = 0
8x2 + 2x -3 = 0
8x2 - 2x – 3 = 0
Correct answer is D
X2 - (sum of the roots)x + (product of the roots) = 0
Sum of the roots \(= -\frac{1}{2}+\frac{3}{4} = \frac{-2+3}{2}=\frac{1}{4}\)
Product of the roots = \(-\frac{1}{2}\times \frac{3}{4}=\frac{-3}{8}\\
X^2-\left(\frac{1}{4}\right)x-\frac{3}{8} = 0. Taking \hspace{1mm}the\hspace{1mm} common\)
\(8x^2-2x-3=0\);
The values of x when y = 3 are approximately
-4.7 and 1.4
-4.6 and 1.5
-3.6 and 0.4
-3.6 and 1.5
Correct answer is B
No explanation has been provided for this answer.
Use the graph to answer the Question below
What are the roots of the equation x2 + 3x - 4 = 0?
1, 4
-1, -4
-1, 4
-4, 1
Correct answer is D
x2 + 3x – 4 = 0 has roots value at the curve makes touches with the x – axis. The curve contact is at x = -4 and +1.
The diagram is a circle centre O. Find the value of x
30o
50o
61o
78o
65.5\(^{\circ}\)
Correct answer is E
∠PQR (Reflex) = 360° – 68° = 292°
∠PQR = 2∠PQR
292° = 4x + 30°
4x = 292 – 30 = 262
\(x = \frac{262}{4}=65.5°\)