How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
10o
25o
35o
60o
Correct answer is B
MPQ = PQM = 3x; ∆MPQ
MPQ + PQM + PMQ = 180° 3x + 3x + 30° = 180°
\(6x \times 30° = 180° 6x + 180° - 30°; 6x + 150°\)
\(x = \frac{150}{6} = 25^{\circ}\)
Given that \(\sqrt{128}+\sqrt{18}-\sqrt{K} = 7\sqrt{2}\), find K,
8
16
32
48
Correct answer is C
\(\sqrt{128} +\sqrt{18}-\sqrt{k}=7\sqrt{2}\\
\sqrt{2\times 64}+\sqrt{9\times 2} - \sqrt{k} = 7\sqrt{2}\\
8\sqrt{2} + 3\sqrt{2} - \sqrt{k} = 7\sqrt{2}; 11\sqrt{2} - \sqrt{k} = 7\sqrt{2}\\
-\sqrt{k}=7\sqrt{2}-11\sqrt{2}; -\sqrt{k} = -4\sqrt{2}; \sqrt{k}=4\sqrt{2}\\
=\sqrt{4^2\times 2} = \sqrt{16\times 2}; \sqrt{k}=\sqrt{32}; k = 32\)
Find the average of the first four prime numbers greater than10
20
19
17
15
Correct answer is D
First four prime numbers greater than 10 are 11, 13, 17, 19
The average \(= \frac{11+13+17+19}{4}=15\)
In the diagram, O is the centre of the circle where OS//QR and ∠SOR = 35o
35o
45o
55o
70o
Correct answer is C
∠SOR = ∠ORQ alternate angle.
Also ∠OQR = ∠OQR (Base angle of isosceles)
∠QOR = 108 – 2(35o) = 180 - 70o - 110o ∠QPR = 1/2QOR = 1/2(110o) ∠QPR + 55o (theorem angle at center is twice angle at circumference)
A point X is on the bearing 342° from a point Y. What is the bearing of Y from X?
342o
252o
198o
162o
Correct answer is D
If x is the bearing 342° from a point y
= 360° - 342° = 18°
The bearing of y from x = 180° - 18° = 162°