How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
In the diagram, POQ is the diameter of the circle centre O. Calculate ∠QRS
35o
70o
100o
125o
Correct answer is A
∠PSQ = 90° (angle in a semi-circle)
(when SR is joined to SP)
∠SPQ = 180 – (90+35) = 180 – 125 = 55°
∠QRS + ∠SPQ = 180° (opposite angles in a cyclic quad is supplementary)
∠QRS = 180° - 55°
= 125°
Given that x + y = 7 and 3x-y = 5, evaluate \(\frac{y}{2}-3\).
-1
1
3
4
Correct answer is A
\(x + y = 7 ------ I\\
3x – y = 5 ------ II\)
Add I and II;
\(4x = 12 => x = \frac{12}{4} = 3\\
Y = 7 – 3 = 4, evaluate \hspace{1mm} \frac{y}{2} – 3\\
\frac{4}{2} – 3 => 2-3 = -1\)
8√3cm2
12√3cm2
16√2cm2
16√3cm2
Correct answer is D
|AB| = 4cm
|BC| = 8cm
In right-angled BAC;
8\(^2\) = 4\(^2\) + |AC|\(^2\)
|AC|\(^2\) = 8\(^2\) - 4\(^2\)
|AC\\(^2\) = 64 - 16 → 48
|AC| = \(\sqrt{48}\)cm → \(4\sqrt{3}cm\)
The area of rectangle = L x B
= |AB| x |AC|
= \((4 \times 4\sqrt{3}cm^2\)
=\(16\sqrt{3}cm^2\)
62.35m
20.78m
18.00m
10.39m
Correct answer is B
Where H is the height of the tower H = ?
\(Tan 30^{\circ} = \frac{H}{36} \Rightarrow H = 36 \times tan30^{\circ}\\
H = 36 \times 0.5774 = 20.79\)
33
8
7
0
Correct answer is C
\(7\frac{1}{2}-\left(2\frac{1}{2}+3\right)\div16\frac{1}{2}\); \(\frac{15}{2} - \left(\frac{5}{2}+\frac{3}{1}\right)\div \frac{33}{2}\)
\(\frac{15}{2} - \left(\frac{5+6}{2}\right)\div \frac{33}{2}\); \(\frac{15}{2} - \frac{11}{2} \div \frac{33}{2}\)
\(\frac{11}{2}\) ÷ \(\frac{33}{2}\) = \(\frac{11}{2}\) * \(\frac{2}{33}\)
= \(\frac{11}{33}\) or \(\frac{1}{3}\) (when simplified)
\(\frac{15}{2}\) - \(\frac{1}{3}\) = \(\frac{43}{6}\)
7.166
The nearest whole number is 7