How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
55cm2
25cm2
22cm2
13cm2
Correct answer is A
Considering the triangle in the diagram
\(tan\theta = \frac{opp}{hyp}\\
Tan 63^{\circ} = \frac{h}{4}\\
h = 4 tan 63^{\circ}\\
Area of trapezium = \frac{1}{2}h(a+b)\\
\left(\frac{1}{2} \times 4 tan 63^{\circ}[5+9]\right)\\
=28\times 1.963 = 54.96 = 55cm^2\)
90o
75o
60o
45o
Correct answer is C
No explanation has been provided for this answer.
Evaluate Cos 45o Cos 30o - Sin 45o Sin 30o leaving the answer in surd form
\(\frac{\sqrt{2}-1}{2}\)
\(\frac{\sqrt{3}-\sqrt{2}}{4}\)
\(\frac{\sqrt{6}-\sqrt{2}}{2}\)
\(\frac{\sqrt{6}-\sqrt{2}}{4}\)
Correct answer is D
\(cos45^o \times cos30^o - sin45^o \times sin30^o\\
\frac{1}{\sqrt{2}}\times \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}}\times \frac{1}{2}\\
\frac{\sqrt{3}}{2\sqrt{2}}-\frac{1}{2\sqrt{2}}; = \frac{\sqrt{3}-1}{2\sqrt{2}}=\frac{\sqrt{6}-\sqrt{2}}{4}\)
Find the equation whose roots are \(-\frac{2}{3}\) and 3
3x2+11x-6=0
3x2+7x+6=0
3x2-11x-6=0
3x2-7x-6=0
Correct answer is D
\(x = -\frac{2}{3} \implies x + \frac{2}{3} = 0\)
\(x = 3 \implies x - 3 = 0\)
\(\implies (x - 3)(x + \frac{2}{3}) = 0\)
\(x^2 - 3x + \frac{2}{3}x - 2 = 0\)
\(x^2 - \frac{7}{3}x - 2 = 0\)
\(3x^2 - 7x - 6 = 0\)
The locus of points equidistant from two intersecting straight lines PQ and PR is
a circle centre P radius Q.
a circle centre P radius PR
the point of intersection of the perpendicular bisectors of PQ and PR
the bisector of angle QPR
Correct answer is C
No explanation has been provided for this answer.