How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
1-(x-y)+xy
1-(x+y)-xy
1-(x+y)+xy
1 - (x - y) + x
Correct answer is C
Prob (passing English) = x
Prob (passing Maths) = Y
Prob (failing English) = 1 - x
Prob (failing Maths) = 1 - y
Prob (failing both test) = Prob(failing English) and Prob(failing Maths) = (1 - x)(1 - y)
=1 - y - x + xy
=1 - (y + x) + xy
p varies as the square of r
p varies as the square root of r
p varies inversely as the square of r
p varies inversely as r
Correct answer is D
\(p \propto q^2\)
\(q\propto\frac{1}{\sqrt{r}}\)
\(p = kq^2\)
\(q = \frac{c}{\sqrt{r}}\)
where c and k are constants.
\(q^2 = \frac{c^2}{r}\)
\(p = \frac{kc^2}{r}\)
If k and c are constants, then kc\(^2\) is also a constant, say z.
\(p = \frac{z}{r}\)
p varies inversely as r.
The square root of a number is 2k. What is half of the number
\(\sqrt{\frac{k}{2}}\)
\(\sqrt{k}\)
\(\frac{1}{2}k^2\)
2k2
Correct answer is D
Let the number be x.
\(\sqrt{x} = 2k \implies x = (2k)^2\)
= \(4k^2\)
\(\frac{1}{2} \times 4k^2 = 2k^2\)
From the Venn Diagram below, find Q' ∩ R.
(e)
(c, h)
(c, g, h)
(c, e, g, h)
Correct answer is C
Q' ∩ R Q' = U - Q Q' = {a, b, c, d, g, h, i} R = {c, e, h, g} Q' ∩ R = {c, h, g}
From the Venn diagram below, how many elements are in P∩Q?
1
2
4
6
Correct answer is B
P \(\cap\) Q = {f, e} = 2