How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Find the value of x in the equation 3x\(^2\) - 8x - 3 = 0
\(\frac{1}{3},-3\)
\(-\frac{1}{3},-3\)
\(-\frac{1}{3},3\)
\(\frac{1}{3},3\)
Correct answer is C
3x\(^2\) - 8x - 3 = 0
3x\(^2\) - 9x + x - 3 = 0
3x(x - 3) + 1(x - 3) = 0
(3x + 1)(x - 3) = 0
3x = -1 \(\implies\) x = \(-\frac{1}{3}\)
or x = 3.
In the diagram, ZM is a straight line. Calculate the value of x.
27o
30o
35o
37o
Correct answer is C
The sum of angles in a triangle is 180o
2xo + (2x -21)o + ∠ZYP = 180o
Also ∠ZYP = 180o - (3x+14)o
∴2xo + (2x-21)o + 180o - (3x+14)o = 180
x = 35o
PQRS is a cyclic quadrilateral. If ∠QPS = 75°, what is the size of ∠QRS?
180o
150o
105o
75o
Correct answer is C
< QPS = 75°
< QRS = 180° - 75° = 105° (opposite angles of a cyclic quadrilateral)
5cm
9cm
12cm
15cm
Correct answer is C
\(V= \frac{1}{2}\hspace{1mm}base\hspace{1mm}area\hspace{1mm}\times\hspace{1mm}height\\
120=\frac{1}{3}\times 5 \times 6 \times h; h = \frac{120}{10}=12cm\)
Evaluate \(\frac{log8}{log\left(\frac{1}{4}\right)}\)
-2
\(\frac{-3}{2}\)
\(\frac{1}{2}\)
4
Correct answer is B
\(\frac{log8}{log\frac{1}{4}}=\frac{log2^3}{log2^{-2}}=\frac{3log2}{-2log2}=-\frac{3}{2}\)