Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

2,921.

A solid cylinder of radius 7cm is 10 cm long. Find its total surface area.

A.

\(70\pi cm^2\)

B.

\(189\pi cm^2\)

C.

\(210\pi cm^2\)

D.

\(238\pi cm^2\)

Correct answer is D

S = \(2\pi r^2 + 2\pi rh\)

= \(2\pi r(r + h)\)

= \(2\pi (7) (7 + 10)\)

= \(238\pi cm^2\)

2,922.

The diagram shows a triangular prism of length 7cm. The right - angled triangle PQR is a cross section of the prism |PR| = 5cm and |RQ| = 3cm. What is the volume of the prism?

A.

28cm2

B.

42cm2

C.

70cm2

D.

84cm2

Correct answer is B

Volume of prism = Area x height

In \(\Delta\) RQP, QR\(^2\) + QP\(^2\) = RP\(^2\)

3\(^2\) + QP\(^2\) = 5\(^2\)

QP\(^2} = 5\(^2\) - 3\(^2\)

QP = \(\sqrt{16}\)

= 4 cm 

\(\therefore\) Area = \(\frac{1}{2} \times base \times height\)

= \(\frac{1}{2} \times 3 \times 4\)

= 6 cm\(^2\)

Volume = 6 x 7

= 42 cm\(^3\)

2,923.

The diagram shows a triangular prism of length 7cm. The right-angled triangle PQR is a cross-section of the prism |PR| = 5cm and |RQ| = 3cm. What is the area of the cross-section?

A.

4cm2

B.

6cm2

C.

15cm2

D.

20cm2

Correct answer is B

In \(\Delta\) RQP, QR\(^2\) + QP\(^2\) = RP\(^2\)

3\(^2\) + QP\(^2\) = 5\(^2\)

QP\(^2} = 5\(^2\) - 3\(^2\)

QP = \(\sqrt{16}\)

= 4 cm 

\(\therefore\) Area = \(\frac{1}{2} \times base \times height\)

= \(\frac{1}{2} \times 3 \times 4\)

= 6 cm\(^2\)

2,924.

In the diagram, MN||PQ, |LM| = 3cm and |LP| = 4cm. If the area of ∆LMN is 18cm2, find the area of the quadrilateral MPQN

A.

3cm2

B.

6cm2

C.

14cm2

D.

24cm2

Correct answer is C

\(\frac{LM}{LP} = \frac{3}{4}\)

\(\frac{Area of LMN}{Area of LPQ} = \frac{3^2}{4^2}\)

Area of LPQ = \(\frac{16}{9}\times 18 = 32 cm^2\)

Area of quadrilateral MPQN = 32 – 18 = \(14 cm^2\)

2,925.

A sector of a circle radius 14 cm subtends an angle 135° at the center of the circle. What is the perimeter of the sector? Take \(\pi = \frac{22}{7}\)

A.

47cm

B.

61cm

C.

88cm

D.

231cm

Correct answer is B

Perimeter of the sector = \(2r + \frac{\theta}{360} \times 2\pi r\)

= \(2(14) + \frac{135}{360} \times 2 \times \frac{22}{7} \times 14\)

= \(28 + 33\)

= 61 cm