How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Which of the following is represented by the above sketch?
y = x2 + x - 6
y = x2 - x - 6
y = x2 - x + 6
y = x2 + x + 6
Correct answer is B
From the graph, the zeros of the equation exist at x = -2 and x = 3
\(\therefore\) (x + 2) = 0 and (x - 3) = 0
\(\implies (x + 2)(x - 3) = 0\)
\(x^2 - 3x + 2x - 6 = 0\)
\(x^2 - x - 6 = 0\) is the equation represented on the graph.
If (-3, -4) is a point on the line y = mx + 2 find the value of m.
-2
\(\frac{7}{4}\)
2
\(\frac{8}{3}\)
Correct answer is C
If (-3, -4) is a point on the line then
-4 = -3m + 2
-4 - 2 = -3m
-6 = -3m
m = 2
Find the nth term of the sequence 4, 10, 16 ,...
2(3n- 1)
2(2 + 3 n-1)
2 n + 2
2(3n+2)
Correct answer is A
\(T_{1} = 4; T_2 = 10; T_3 = 16\)
\(T_{2} - T_1 = T_3 - T_1 = 6\)
\(T_n = a + (n - 1) d\)
= \(4 + (n - 1) \times 6\)
= \(4 + 6n - 6\)
= \(6n - 2\)
= 2(3n - 1)
From the diagram, find the bearing of Q from P.
236o
214o
146o
124o
Correct answer is A
No explanation has been provided for this answer.
If (x + 3) varies directly as y and x = 3 when y = 12, what is the value of x when y = 8?
1
\(\frac{1}{2}\)
\(-\frac{}{}\)
-1
Correct answer is A
\((x+3) \propto y\\
∴x + 3 = ky\hspace{1mm}when\hspace{1mm}x = 3, y = 12\\
3+3 = 12k\\
∴ k = \frac{1}{2}\\
\Longrightarrow x + 3 = \frac{1}{2}y\) to find x when y = 8
\(x + 3 = \frac{1}{2}\times 8\\
x=4-3\\
x = 1\)