How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Simplify \(3\sqrt{12} + 10\sqrt{3} - \frac{6}{\sqrt{3}}\)
\(7\sqrt{3}\)
\(10\sqrt{3}\)
\(14\sqrt{3}\)
\(18\sqrt{3}\)
Correct answer is C
\(3\sqrt{12} + 10\sqrt{3} - \frac{6}{\sqrt{3}}\)
= \(3(\sqrt{4 \times 3}) + 10\sqrt{3} - (\frac{6}{\sqrt{3}})(\frac{\sqrt{3}}{\sqrt{3}})\)
= \(6\sqrt{3} + 10\sqrt{3} - 2\sqrt{3}\)
= \(14\sqrt{3}\)
The volume of a cylinder of radius 14cm is 210cm3. What is the curved surface area of the cylinder?
15cm2
30cm2
616cm2
1262cm2
Correct answer is B
\(V = \pi r^2 h\\
210 = \frac{22}{7} \times 14^2 \times h \\
h = \frac{210}{22 \times 28}\)
Curved surface area \(= 2r\pi h\\
= 2 \times \frac{22}{7} \times 14 \times \frac{210}{22 \times 26} = 30cm^2\)
35.75m
25.00m
22.98m
19.28
Correct answer is A
\(\tan 40° = \frac{30}{|PQ|}\)
\(|PQ| = \frac{30}{\tan 40°} = \frac{30}{0.839}\)
= 35.75m
42o
39o
38o
30o
Correct answer is A
No explanation has been provided for this answer.
Simplify \(\frac{2^{\frac{1}{2}}\times 8^{\frac{1}{2}}}{4}\)
1
2
4
16
Correct answer is A
\(\frac{2^{\frac{1}{2}}\times 8^{\frac{1}{2}}}{4}\\=\frac{2^{\frac{1}{2}}\times 2^{\frac{3}{2}}}{2^2}\\=2^{\frac{1}{2}}+2^{\frac{3}{2}}-2=2^0 = 1\)