Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

2,896.

The base diameter of a cone is 14cm, and its volume is 462 cm3. Find its height. [Taken \(\pi = \frac{22}{7}\)]

A.

3.5cm

B.

5cm

C.

7cm

D.

9cm

Correct answer is D

From \(V = \frac{1}{3}\pi r^2 h. \hspace{1mm} r =\frac{14}{2}\\
462 = \frac{1}{3} \times \frac{22}{7} \times 7^2 \times h \\
h = \frac{3 \times 462}{22 \times 7}\\ h = 9\)

2,897.

The lengths of the parallel sides of a trapezium are 9 cm and 12 cm. lf the area of the trapezium is 105 cm2, find the perpendicular distance between the parallel sides.

A.

5cm

B.

7cm

C.

10cm

D.

15cm

Correct answer is C

\(\frac{1}{2}(a+b)\times h = 105cm^2\\
\frac{1}{2}(9+12)\times h = 105\\
h = \frac{105 \times 2}{21} = 10cm\)

2,898.

Simplify \(\frac{1}{1-x} + \frac{2}{1+x}\)

A.

\(\frac{x+3}{1-x^2}\)

B.

\(\frac{x-3}{1+x^2}\)

C.

\(\frac{3-x}{1-x^2}\)

D.

\(\frac{3-x}{1+x^2}\)

Correct answer is C

\(\frac{1}{1-x} + \frac{2}{1+x}\\
\frac{1+x+2-2x}{(1-x)(1+x)} = (\frac{3-x}{1-x^2})\)

2,899.

For what values of x is the expression \(\frac{3x-2}{4x^2+9x-9}\) undefined?

A.

\(\frac{-3}{4} \hspace{1mm}or \hspace{1mm}3\)

B.

\(\frac{-2}{3} \hspace{1mm}or \hspace{1mm}-3\)

C.

\(\frac{2}{3} \hspace{1mm}or \hspace{1mm}3\)

D.

\(\frac{3}{4} \hspace{1mm}or \hspace{1mm}-3\)

Correct answer is D

The equation \(\frac{3x - 2}{4x^2 + 9x - 9}\) is undefined when the denominator = 0.

\(4x^2 + 9x - 9 = 0\)

\(4x^2 + 12x - 3x - 9 = 0\)

\(4x(x + 3) - 3(x + 3) = 0\)

\((4x - 3)(x + 3) = 0\)

x = \(\frac{3}{4}\) or x = -3.

2,900.

In the diagram, SQ is a tangent to the circle at P, XP||YQ, ∠XPY = 56o and ∠PXY = 80o.Find angle PQY

A.

34o

B.

13.36o

C.

44o

D.

46o

Correct answer is A

< XYQ = 180° - (80° + 56°)

= 44°

< PYQ = 56° (alternate angles, XP||YQ)

< QPY = 90°

< PQY = 180° - (90° + 56°)

= 34°