How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
If \(\frac{y-3}{2}<\frac{2y-1}{3}\), which of the following is true?
y > 7
y < -7
y > -7
y < 7
Correct answer is C
\(\frac{y - 3}{2} < \frac{2y - 1}{3}\)
\(3(y - 3) < 2(2y - 1)\)
\(3y - 9 < 4y - 2\)
\(3y - 4y < -2 + 9\)
\(-y < 7\)
\(y > -7\)
Simplify \(\frac{2x-1}{3}-\frac{x+3}{2}\)
\(\frac{x+3}{6}\)
\(\frac{x+8}{6}\)
\(\frac{x-11}{6}\)
\(\frac{x-4}{6}\)
Correct answer is C
\(\frac{2x - 1}{3} - \frac{x + 3}{2}\)
= \(\frac{2(2x - 1) - 3(x + 3)}{6}\)
= \(\frac{4x - 2 - 3x - 9}{6}\)
= \(\frac{x - 11}{6}\)
(6x - 5)(x + 4)
2(3x-5)(x+2)
(3x+4)(2x-5)
(3x-4)(2x+5)
Correct answer is D
\(6x^2 + 7x - 20\)
= \(6x^2 + 15x - 8x - 20\)
= \(3x(2x + 5) - 4(2x + 5)\)
= \((3x - 4)(2x + 5)\)
Evaluate \(\frac{x^2 + x - 2}{2x^2 + x -3}\) when x = -1
-2
-1
\(-\frac{1}{2}\)
1
Correct answer is D
\(\frac{x^2 + x - 2}{2x^2 + x - 3}\)
= \(\frac{x^2 + 2x - x - 2}{2x^2 + 3x - 2x - 3}\)
= \(\frac{x(x + 2) - 1(x + 2)}{x(2x + 3) - 1(2x + 3)}\)
= \(\frac{(x - 1)(x + 2)}{(x - 1)(2x + 3)}\)
= \(\frac{x + 2}{2x + 3}\)
At x = -1,
= \(\frac{-1 + 2}{2(-1) + 3}\)
= \(\frac{1}{1}\)
= 1
Given that y = px + q and y = 5 when x = 3, while y = 4 when x = 2, find the value of p and q.
p = 1, q = 3
p = 1, q = 2
p = -2, q = 3
p = 3, q = -2
Correct answer is B
y = px + q
5 = 3p + q ... (i)
4 = 2p + q ... (ii)
(i) - (ii) : p = 1
∴∴ 5 = 3(1) + q
⟹⟹ q = 5 - 3 = 2
(p, q) = (1, 2)