Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

2,971.

In the diagram, |PQ| = |PS| Which of the following statements is true?

A.

∠QPS = QRS

B.

|PO| = |RO|

C.

QR||PS

D.

∠PQR=∠PSR

Correct answer is D

No explanation has been provided for this answer.

2,972.

The arc of a circle 50 cm long, subtends angle of 75° at the center of the circle. Find correct to 3 significant figures, the radius of the circle. Take \(\pi = \frac{22}{7}\)

A.

8.74cm

B.

38.2cm

C.

61.2cm

D.

76.4cm

Correct answer is B

Length of arc = \(\frac{\theta}{360} \times 2\pi r\)

\(50 = \frac{75}{360} \times 2 \times \frac{22}{7} \times r\)

\(r = \frac{50 \times 360 \times 7}{75 \times 2 \times 22}\)

\(r = \frac{420}{11}\)

= 38.18 cm \(\approxeq\) 38.2 cm (3 sig. figs)

2,973.

The length of the parallel sides of a trapezium are 5cm and 7cm. If its area is 120cm\(^2\), find the perpendicular distance between the parallel sides

A.

5.0cm

B.

6.9cm

C.

10.0cm

D.

20.0cm

Correct answer is D

Area of trapezium = \(\frac{1}{2} (a + b)h\)

\(120 = \frac{1}{2} (5 + 7) \times h\)

\(120 = 6h\)

\(h = 20 cm\)

2,974.

A tap leaks at the rate of 2cm\(^3\) per seconds. How long will it take the tap to fill a container of 45 liters capacity? (1 liters = 1000cm\(^3\))

A.

8 hours

B.

6hr 15min

C.

4hr 25min

D.

3 hours

Correct answer is B

Total capacity of the container = 45 liters = 45 x 1000 

= 45000 cm\(^3\)

Time to fill the container = \(\frac{45000}{2}\)

= 22500 seconds

= \(\frac{22500}{3600}\)

= 6 hr 15 mins

2,975.

The height of a pyramid on square base is 15cm. if the volume is 80cm^3, find the area of the square base.

A.

8cm2

B.

9.6cm2

C.

16cm2

D.

25cm2

Correct answer is C

Volume of pyramid with square base = \(\frac{\text{base area} \times height}{3}\)

\(80 = \frac{\text{base area} \times 15}{3}\)

\(80 = 5 \times \text{base area}\)

\(\text{Base area} = 16 cm^2\)