How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Make t the subject of formula \(k = m\sqrt{\frac{t-p}{r}}\)
\(\frac{rk^2 + p}{m^2}\)
\(\frac{rk^2+pm^2}{m^2}\)
\(\frac{rk^2-p}{m^2}\)
\(\frac{rk^2-p^2}{m^2}\)
Correct answer is B
\(k = m\sqrt{\frac{t - p}{r}}\)
\(\frac{k}{m} = \sqrt{\frac{t - p}{r}}\)
\((\frac{k}{m})^2 = \frac{t - p}{r}\)
\(rk^2 = m^2 (t - p)\)
\(\therefore m^2 t = rk^2 + m^2 p\)
\(t = \frac{rk^2 + m^2 p}{m^2}\)
Find the equation whose roots are -8 and 5
\(x^2 + 13x + 40=0\)
\(x^2 - 13x - 40=0\)
\(x^2 - 3x +40=0\)
\(x^2 + 3x - 40=0\)
Correct answer is D
Equation with roots -8 and 5: (x + 8)(x - 5) = 0
\(x^2 - 5x + 8x - 40 = 0\)
\(x^2 + 3x - 40 = 0\)
Form an inequality for a distance d meters which is more than 18m, but not more than 23m
18 ≤ d ≤ 23
18 < d ≤ 23
18 ≤ d < 23
d < 18 or d > 23
Correct answer is B
No explanation has been provided for this answer.
Simplify \(\frac{1}{x-3}-\frac{3(x-1)}{x^2 - 9}\)
\(\frac{x-1}{x-3}\)
\(\frac{-2}{x+3}\)
\(\frac{x-1}{x+3}\)
\(\frac{4x}{x^2-9}\)
Correct answer is B
\(\frac{1}{x-3}-\frac{3(x-1)}{x^2 - 9}\\
\frac{1}{x-3}-\frac{3(x-1)}{(x-3)(x+3)}\\
\frac{x+3-3x+3}{(x-3)(x+3)};\frac{-2x+6}{(x-3)(x+3)}\\
\frac{-2(x-3)}{(x-3)(x+3)}=\frac{-2}{x+3}\)
Given that (2x + 7) is a factor of \(2x^2 + 3x - 14\), find the other factor
x + 2
2 - x
x - 2
x + 1
Correct answer is C
\(2x^2 + 3x - 14\)
\(2x^2 + 7x - 4x - 14\)
\(x(2x + 7) - 2(2x + 7)\)
= \((x - 2)(2x + 7)\)
The other factor = (x - 2).