How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Simplify 3.72 x 0.025 and express your answer in the standard form
\(9.3\times 10^3\)
\(9.3\times 10^2\)
\(9.3\times 10^{-2}\)
\(9.3\times 10^{-3}\)
Correct answer is C
\(3.72 \times 0.025 = 0.093 = 9.3\times 10^{-2}\)
3.3cm
5.3cm
4.0cm
8.0cm
Correct answer is C
Volume = \(\frac{1}{3} b^2 h\)
\(\therefore b = \sqrt{\frac{3v}{h}}\)
\(b = \sqrt{\frac{3(80)}{15}} \)
\(b = \sqrt{16} = 4.0 cm\)
In the diagram, PQST and QRST are parallelograms. Calculate the area of the trapezium PRST.
60cm2
50cm2
40cm2
30cm2
Correct answer is D
PR = 4 + 4 = 8 cm
Area of trapezium = \(\frac{1}{2} (a + b) h\)
= \(\frac{1}{2} (4 + 8) \times 5\)
= 30 cm\(^2\)
\(16\sqrt{3}m\)
\(4\sqrt{3}m\)
\(\frac{\sqrt{3}}{16}\)
\(\frac{16\sqrt{3}}{3}\)
Correct answer is D
\(sin 60 = \frac{8}{L} = 8 \div \frac{\sqrt{3}}{2}; L = \frac{8}{sin 60}=\frac{16}{\sqrt{3}}\)
When we rationalize gives \(\frac{16\sqrt{3}}{3}\)
040o
070o
110o
290o
Correct answer is D
< ABC = 40° (alternate angles)
\(\therefore\) < ACB = \(\frac{180° - 40°}{2}\)
= 70°
\(\therefore\) Bearing of A from C = 360° - 70°
= 290°