How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Given that \(81\times 2^{2n-2} = K, find \sqrt{K}\)
\(4.5\times 2^{n}\)
\(4.5\times 2^{2n}\)
\(9\times 2^{n-1}\)
\(9\times 2^{2n}\)
Correct answer is C
\(K = 81 \times 2^{2n - 2}\)
\(\sqrt{K} = \sqrt{81 \times 2^{2n - 2}}\)
= \(9 \times 2^{n - 1}\)
If \(y = \sqrt{ax-b}\) express x in terms of y, a and b
\(x = \frac{y^2-b}{a}\)
\(x = \frac{y+b}{a}\)
\(x = \frac{y-b}{a}\)
\(x = \frac{y^2 + b}{a}\)
Correct answer is D
\(y = \sqrt{ax-b}\)
\(y^2 = ax-b\)
\(y^2 +b = ax\)
\(x = \frac{y^2 + b}{a}\)
Simplify \(\frac{2-18m^2}{1+3m}\)
\(2(1+3m)\)
\(2(1+3m^2)\)
\(2(1-3m)\)
\(2(1-3m^2)\)
Correct answer is C
\(\frac{2-18m^2}{1+3m}=\frac{2(1-(3m)^2)}{1+3m}\)
\(frac{2(1-(3m)(1+3m)}{1+3m}=2(1-3m)\)
Given that m = -3 and n = 2 find the value of \(\frac{3n^2 - 2m^3}{m}\)
-22
-14
14
22
Correct answer is A
Given that m = -3, n = 2, the value of
\(\frac{3n^2 - 2n^3}{m}\\
\frac{3(2)^2 -2(-3)^2}{-3}= \frac{12+54}{-3}=-22\)
In the diagram, POR is a circle with center O. ∠QPR = 50°, ∠PQO = 30° and ∠ORP = m. Find m.
20o
25o
30o
50o
Correct answer is A
< QOR = 50° x 2 = 100°
Reflex < QOR = 360° - 100° = 260°
\(\therefore\) 30° + 50° + 260° + m = (4 - 2) x 180°
340° + m = 360°
m = 360° - 340° = 20°