\(x = \frac{y^2-b}{a}\)
\(x = \frac{y+b}{a}\)
\(x = \frac{y-b}{a}\)
\(x = \frac{y^2 + b}{a}\)
Correct answer is D
\(y = \sqrt{ax-b}\)
\(y^2 = ax-b\)
\(y^2 +b = ax\)
\(x = \frac{y^2 + b}{a}\)
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