How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Find (X-Y) if 4x - 3y = 7 and 3x - 2y = 5
4
3
2
-2
-3
Correct answer is C
No explanation has been provided for this answer.
Find the equation whose roots are \(\frac{2}{3}and \frac{-1}{4}\)
\(12x^2-5x+2=0\)
\(12x^2-11x+2=0\)
\(x^2-\frac{11}{12}x+2=0\)
\(x^2+\frac{11}{12}x-2=0\)
\(12x^2+11x+2=0\)
Correct answer is A
x\(^2\) - (sum of given roots)x + (product of given roots ) = 0
x\(^2\) - (\(\frac{2}{3} + \frac{-1}{4}\))x + (\(\frac{2}{3} * \frac{-1}{4}\)) = 0
x\(^2\) - (\(\frac{8 - 3}{12}\))x + (\(\frac{- 2}{12}\))
x\(^2\) - \(\frac{5}{12}\)x + \(\frac{- 2}{12}\)
multiply through by the LCM 12
12 * x\(^2\) - 12 * \(\frac{5}{12}\)x + 12 * \(\frac{- 2}{12}\)
12x\(^2\) - 5x - 2 = 0
Make S the subject of the formula: \(V = \frac{K}{\sqrt{T-S}}\)
\(T-\frac{K^2}{V^2} = S\)
\(T+\frac{K^2}{V^2} = S\)
\(T-\frac{K^2}{V} = S\)
\(T-\frac{K}{V} = S\)
\(T-\frac{K}{V^2} = S\)
Correct answer is A
\(V = \frac{K}{\sqrt{T-S}}\)
square both sides of the equation
\(V^2 = \frac{K^2}{T-S}\)
cross multiply
\(V^2 T - S = K^2\)
\(T - S = \frac{K^2}{V^2}\)
\(T = \frac{K^2}{V^2} + S\)
\(T - = \frac{K^2}{V^2} = S\)
For what value of x is the expression x - 5x2 - 2x - 3 not defined?
3, 1
-1, -3
-1, 3
3, -2
1, -3
Correct answer is C
x2 - 2x - 3 = 0
x2 - 3x + x - 3 = 0
x(x - 3) + (x - 3) = 0
(x + 1)(x - 3) = 0
x = -1 or 3
-p < -2q
-p > -2q
-q < 2p
q < 1/2p
p2 > 2q2
Correct answer is B
No explanation has been provided for this answer.