How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Find the quadratic equation whose roots are 3 and \(\frac{2}{3}\).
x2 - 11 / 3x + 6 = 0
x2 - 11x + 6 = O
3x2 - 11x + 2 = O
3X2 - 11x – 2 = 0
3x2 - 11x + 6 = 0
Correct answer is E
x = 3; x = \(\frac{2}{3}\).
(x - 3)(x - \(\frac{2}{3}\)) = 0
\(x^2 - \frac{2x}{3} - 3x + 2 = 0\)
\(x^2 - \frac{11x}{3} + 2 = 0\)
\(3x^2 - 11x + 6 = 0\)
Which of the following is not a factors of 2p\(^2\) - 2?
2
p - 1
p + 1
2p - 2
2p + 1
Correct answer is E
2p\(^2\) - 2
2(p\(^2\) - 1)
= 2(p + 1)(p - 1)
x2 - 2 = 0
x2 - 4 = 0
x2 + 6 = 0
X2 - X – 2 = 0
x2 - x + 4 = 0
Correct answer is B
The points of intersection of the curve and the line are at x = -2 and x = 2.
\(\therefore\) (x + 2) = 0; (x - 2) = 0.
(x + 2)(x - 2) = 0
\(x^2 - 4 = 0\)
What is the equation of the line PQ?
y = x - 5
y = x + 3
y = x + 5
y = 2x + 3
y = 2x - 3
Correct answer is C
The points P(-2, 3) and Q(2, 7) are on the line.
Gradient of the line = \(\frac{7 - 3}{2 - (-2)}\)
= \(\frac{4}{4}\)
= 1
y = x + b
To find the intercept, we have
7 = 2 + b or 3 = -2 + b.
Solving for b, we get b = 5.
\(\therefore\) The line is y = x + 5.
In the graph above, the gradient of the curve at the point P is
-11 3
-3 4
3/7
3/4
11 3
Correct answer is A
-1-(-3)/-2-(-0.5) = 2/-1.5 = 20/-15 = -113