Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

3,391.

Let U = {1, 2, 3, 4}, P = {2, 3} and Q = {2, 4}. What is (P∩Q)'?

A.

(1, 2, 3)

B.

(1, 3, 4)

C.

(2, 3)

D.

(1, 3)

E.

(1, 4)

Correct answer is B

U = {1,2,3,4}; P = {2,3}; Q = {2,4}; P∩Q = {2} (P∩Q)' = {1,3,4}

3,392.

In the diagram above , |AD| = 10cm, |DC| = 8cm and |CF| = 15cm. Which of the following is correct?

A.

Area BCF = Area DCF

B.

Area ADE = Area ADF

C.

Area ADE = Area DCFE

D.

Area CBF = Area DABC

E.

Area DABO = Area CFEO

Correct answer is E

No explanation has been provided for this answer.

3,393.

In the diagram above , |AD| = 10cm, |DC| = 8cm and |CF| = 15cmIf the area of triangle DCF = 24cm2, find the area of the quadrilateral ABCD.

A.

24cm2

B.

48cm2

C.

80cm2

D.

96cm2

E.

120cm2

Correct answer is B

Area of \(\Delta\)DCF = 24cm2

Area of Quad= 2 x 24 = 48cm2

3,394.

In the diagram above, PQ and XY are two concentric arc; center O, the ratio of the length of the two arc is 1:3, find the ratio of the areas of the two sectors OPQ and OXY

A.

1:3

B.

1:6

C.

1:9

D.

2:3

E.

4:9

Correct answer is C

Let the radius of the arc PQ = r and the radius of the arc XY = R.

Length of arc PQ = \(\frac{\theta}{360} \times 2\pi r = 1\)

Length of arc XY = \(\frac{\theta}{360} \times 2\pi R = 3\)

Ratio of the arc = \(\frac{r}{R} = \frac{360 \times 2\pi \theta}{2\pi \theta \times 360 \times 3}\)

= \(\frac{1}{3}\)

Ratio of their area = \((\frac{1}{3})^2 = \frac{1}{9}\)

= 1 : 9

3,395.

Find the area of an equivalent triangle of side 16cm

A.

64√3cm2

B.

72√3cm2

C.

96cm2

D.

128√3cm2

E.

128cm2

Correct answer is A

Area = 1/2 x 16 x 16sin60o = 64√3cm2