How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Which triangle is equal in area to ΔVWZ
ΔVXZ
ΔVYZ
ΔXYV
ΔWYV
ΔWYZ
Correct answer is B
Area of \(\Delta\) VYZ = Area of \(\Delta\) VWZ (same base and within same parallel)
∠VXZ
∠VYX
∠XZW
∠YXZ
∠VYW
Correct answer is A
< VWZ = < VXZ (angles in the same segment)
In the diagram above PS||RQ, |RQ| = 6.4cm and perpendicular PH = 3.2cm. Find the area of SQR
5.12cm2
9.60cm2
10.24cm2
20.48cm2
40.96cm2
Correct answer is C
Area of a triangle = \(\frac{1}{2} \times b \times h\)
Area of \(\Delta\) SQR = \(\frac{1}{2} \times 6.4 \times 3.2\)
= 10.24 cm\(^2\)
In the diagram above, WXYZ is a rhombus and ∠WYX = 20°. What is the value of ∠XZY
20o
30o
45o
60o
70o
Correct answer is E
Diagonals bisect at 90°; < YXZ = 90° - 20° = 70°
But ZY = XY (sides of a rhombus)
\(\therefore\) < XYZ = 70° (base angle of an isos. triangle)
In the diagram above, |PQ| = |PR| = |RS| and ∠RPS = 32°. Find the value of ∠QPR
72o
64o
52o
32o
26o
Correct answer is C
From the figure, < PSR = 32° (base angles of an isos. triangle)
\(\therefore\) < PRS = 180° - (32° + 32°) = 116° (sum of angles in a triangle)
< QRP = 180° - 116° = 64° (angle on a straight line)
< PQR = 64° (base angles of an isos. triangle)
< QPR = 180° - (64° + 64°) = 52°