How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
If sin\( \theta \) = K find tan\(\theta\), 0° \(\leq\) \(\theta\) \(\leq\) 90°.
1-K
\( \frac{k}{k - 1} \)
\( \frac{k}{\sqrt{1 - k^2}} \)
\( \frac{k}{1 - k} \)
\( \frac{k}{\sqrt{ k^2 - 1}} \)
Correct answer is C
\(\sin \theta = \frac{k}{1}\)
\(\implies 1^2 = k^2 + adj^2\)
\(adj = \sqrt{1 - k^2}\)
\(\therefore \tan \theta = \frac{k}{\sqrt{1 - k^2}}\)
If the 2nd and 5th terms of a G.P are 6 and 48 respectively, find the sum of the first for term
-45
-15
15
33
45
Correct answer is E
T\(_{2}\) = ar = 6
T\(_{5}\) = ar\(^{4}\) = 48
\(\frac{T_5}{T_2}\) = \(\frac{ar^{4}}{ar}\) = \(\frac{48}{6}\)
= r\(^{3}\) = 8
⇒ r = 2
S\(_{n}\) = \(\frac{a((r^n) - 1)}{r - 1}\)
S\(_{4}\) = \(\frac{a((r^4) - 1)}{r - 1}\)
S\(_{4}\) = \(\frac{3((2^4) - 1)}{2 - 1}\)
= 3(16 -1)
= 45
56 cm
22 cm
42 cm
44 cm
Correct answer is D
No explanation has been provided for this answer.
A triangle has vertices P(-1,6), Q(-3, -4) and R(1, -4).Find the midpoint of PQ and QR respectively.
(0,-2) and (-1, -4)
(-1,0) and (-1,-1)
(-2,1) and (0,1)
(-2,1) and (-1,-4)
Correct answer is D
No explanation has been provided for this answer.
Find the equation of the locus of a point P(x,y) which is equidistant from Q(0,0) and R(2,1).
4x + 2y = 5
4x - 2y = 5
2x + 2y = 5
2x + y = 5
Correct answer is A
No explanation has been provided for this answer.