How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
8/15
11/25
12/25
13/25
Correct answer is D
First teacher received \(\frac{2}{5}\) ∴Remainder \(= 1 - \frac{2}{5} = \frac{3}{5}\)
2nd teacher received; \(\frac{2}{15} of \frac{3}{5} = \frac{2}{15} \times \frac{3}{5} = \frac{2}{25}\)
3rd teacher will receive; \(1-\frac{2}{5}-\frac{2}{25}=\frac{25-10-2}{15}\\=\frac{13}{25}\)
96 cm
324 cm
36 cm
144 cm
Correct answer is B
\(L \propto T^2\)
\(L = kT^2\)
\(k = \frac{L}{T^2}\)
when T = 4, L = 64.
\(k = \frac{64}{4^2} = 4\)
\(L = 4T^2\)
when T = 9,
\(L = 4 \times 9^2 = 324cm\)
Find the sum to infinity of the series 1/2 , 1/6, 1/18, .....
2/3
1/3
3/4
1
Correct answer is C
\(a=\frac{1}{2}\\r=\frac{\frac{1}{6}}{\frac{1}{2}}=\frac{1}{6}\times\frac{2}{1}=\frac{1}{3}\\S_\infty = \frac{a}{1-r}\\S_\infty = \frac{\frac{1}{2}}{1-\frac{1}{3}}\\=\frac{\frac{1}{2}}{\frac{3}{2}}\\=\frac{1}{2}\times\frac{3}{2}\\=\frac{3}{4}\)
Factorize completely ac - 2bc - a
(a - 2b)(c - a - 2b)
(a - 2b)(c + a +2b)
(a - 2b)(c - a + 2b)
(a - 2b)(c + a - 2b)
Correct answer is A
ac - 2bc - a2 + 4b2
ac - 2bc - (a2 - 4b2)
ac - 2bc - (a2 -(2b)2)
c(a - 2b) - {(a - 2b)(a + 2b)}
(a - 2b)(c - (a + 2b))
(a - 2b)(c - a - 2b)
18
12
6
3
Correct answer is A
Qn = 3 * 2n - 2
Um = 3 * 22m - 3
Q2 * U2 = (3 * 22 - 2) * (3 * 22(2) - 3)
= 3 * 20 * 3 * 21
= 3 * 1 * 3 * 2
= 18