How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
15/28
13/28
5/14
3/14
Correct answer is A
Black balls = 5
Red balls = 3/8
P(B) = 5/8, P(R) = 3/8
P( a Black and a Red) = BR + RB
= (5/8) * (3/7) * (3/8) * (5/7)
= (15/56) + (15/56)
= 30/56
= 15/28
3
6
18
24
Correct answer is C
\(^{4}C_2 \times ^{3}C_1 = \left(\frac{4!}{(4-2)!2!}\right)\times\left(\frac{3!}{(3-1)!1!}\right)\\=\frac{4!}{2!2!}\times \frac{3!}{2!}\\=\frac{4 \times 3 \times 2!}{2 \times 1 \times 2!} \times \frac{3 \times 2!}{2!}\\=18\)
If \(^{n}P_{3} - 6(^{n}C_{4}) = 0\), find the value of n.
5
6
7
8
Correct answer is C
\(^{n}P_3 - 6(^{n}C_{4})=0\\\frac{n!}{(n-3)!}-6\left( \frac{n!}{(n-4)!4!}\right)=0\\\frac{n!}{(n-3)!}=6\left(\frac{n!}{(n-4)!4!}\right)\\n!((n-4)!4!)=6n!(n-3)!\\((n-4)!4!)=6(n-3)!\\\frac{(n-4)!}{(n-3)!}=\frac{6}{4!}\\\frac{(n-4)!}{(n-3)(n-4)!}=\frac{6}{4 \times 3\times 2\times 1}\\\frac{1}{(n-3)}=]\frac{1}{4}\\n-3=4\\n=4+3\\n=7\)
N96.00
N84.00
N48.00
N42.00
Correct answer is B
Let the 4th angle be = x
∴ x + 45 + 90 + 135 = 360
x + 270 = 360
x = 360 - 270
x = 90
∴ smallest angle = 45o
45o = N28.00
1o = 28.00/45
135o = (28.00/45) * (135/1)
= N84.00
The range of 4, 3, 11, 9, 6, 15, 19, 23, 27, 24,21 and 16 is
16
21
23
24
Correct answer is D
Range = (Highest - Lowest) items
= 27 - 3
= 24