How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
By how much is the mean of 30, 56, 31, 55, 43 and 44 less than the median?
0.75
0.50
0.33
0.17
Correct answer is C
\(Mean = \frac{30+56+31+55+43+44}{6}\\=\frac{259}{6}=43.167\\Median = 30,31,43,44,55,56\\=\frac{43+44}{2}=\frac{87}{2}=43.5\\Median-mean = 43.5-43.17=0.33\)
Determine the maximum value of y = 3x2 - x3
zero
2
4
6
Correct answer is C
y = 3x2 - x3
dy/dx = 6x - 3x2
as dy/dx = 0
6x - 3x2 = 0
3x (2 - x) = 0
this implies that 2 -x = 0 and 3x = 0
x = 2 (or) 0
But = dy/dx = 6x - 3x2
d2y/dx2 = 6 - 6x at x = 2
= 6 - 6(2)
= -6
y = 3x2 - x3
= 3(2)2 - 23
= 12 - 8
= 4
12x cos (4x)
-12x cos (-4x)
-12 cos (-4x)
12 sin (-4x)
Correct answer is C
y = 3 sin(-4x)
dy/dx = 3 x - 4 cos (-4x)
= -12 cos (-4x)
Evaluate \(\int^{2} _{3}(x^2 - 2x)dx\)
4
2
4/3
1/3
Correct answer is C
\(\int^{2} _{3}(x^2 - 2x)dx\\=\left[\frac{x^3}{3}-\frac{2x^2}{2}\right ]^{2}_{3}\\\left[\frac{x^3}{3}-x^2 + C\right ]^{2}_{3}\\\left[\frac{3^3}{3}-3^2 + C \right ]-\left[\frac{2^3}{3}-2^2 + C \right ]\\9-9-\left[\frac{8}{3}-4 \right ]\\=\frac{-8}{3}+4\\=\frac{4}{3}\)
Find the slope of the curve y = 2x\(^2\) + 5x - 3 at (1, 4).
4
6
7
9
Correct answer is D
y = 2x\(^2\) + 5x - 3
dy/dx = 4x + 5
= 4 + 5
= 9