Evaluate ∫23(x2−2x)dx
...Evaluate ∫23(x2−2x)dx
4
2
4/3
1/3
Correct answer is C
∫23(x2−2x)dx=[x33−2x22]23[x33−x2+C]23[333−32+C]−[233−22+C]9−9−[83−4]=−83+4=43
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