From a point R, 300m north of P, a man walks eastwards to a ...
From a point R, 300m north of P, a man walks eastwards to a place; Q which is 600m from P. Find the bearing of P from Q correct to the nearest degree
A.
026o
B.
045o
C.
210o
D.
240o
Correct answer is D
Cos θ = adjhyp
= 300600
= 0.5
θ = Cos - 10.5
= 60
∠ RPQ = ∠ PQs
So the bearing of P from Q is 180 + 60 = 240o
Answer is D
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