How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
If -2 is the solution of the equation 2x + 1 - 3c = 2c + 3x - 7, find the value of c.
4
3
2
1
Correct answer is C
-2 is the solution implies x = -2.
2x + 1 - 3c = 2c + 3x - 7
2(-2) + 1 - 3c = 2c + 3(-2) - 7
-4 + 1 - 3c = 2c - 6 - 7
-3 + 13 = 2c + 3c ⟹⟹ c = 2.
The inverse function f(x) = 3x + 4 is
(x-4)/3
(x-5)/5
(x+3)/4
(x+4)/3
Correct answer is A
Let y = f(x).
\(y = 3x + 4 \implies x = \frac{y - 4}{3}\)
Replace y with x.
\(y = \frac{x - 4}{3} \)
Make r subject of the formula given that \(\frac{x}{r+a}=\frac{a}{r}\)
\(\frac{a^{2}}{(x-a)}\)
\(\frac{a^{2}}{(x+a)}\)
\(\frac{a}{x-a}\)
\(\frac{a}{x+a}\)
Correct answer is A
\(\frac{x}{r + a} = \frac{a}{r}\)
\(\implies rx = ar + a^{2}\)
\(rx - ra = a^{2} \implies r = \frac{a^2}{x - a}\)
If the 9th term of an A.P is five times the 5th term, find the relationship between a and d.
2a + 2 = 0
3a + 5d = 0
a + 3d = 0
a + 2d = 0
Correct answer is C
\(T_{n} = a + (n - 1) d\) (nth term of an AP).
\(T_{9} = 5T_{5}\)
\(a + 8d = 5(a + 4d) \implies a + 8d = 5a + 20d\)
\(5a - a + 20d - 8d = 0 \implies 4a + 12d = 0\)
\(a + 3d = 0\)
Find the maximum value of y in the equation y = 1 - 2x - 3x\(^2\)
5/4
5/3
3/4
4/3
Correct answer is D
\(y = 1 - 2x - 3x^2\)
At maximum point, \(\frac{\mathrm d y}{\mathrm d x} = 0\)
\(\frac{\mathrm d y}{\mathrm d x} = -2 - 6x\)
\(-2 - 6x = 0 \implies -2 = 6x\)
\(x = -\frac{1}{3}\)
At x = \(-\frac{1}{3}\), y = \(1 - 2(-\frac{1}{3}) - 3(-\frac{1}{3})^{2}\)
= \(1 + \frac{2}{3} - \frac{1}{3}\)
= \(\frac{4}{3}\)