If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.
\( 2.93 \times 10^{15}\)Hz
\( 3.59 \times 10^{16}\)Hz
\( 5.39 \times 10^{15}\)Hz
\( 1.24 \times 10^{15}\)Hz
Correct answer is D
h = \( 6.6 \times 10^{-34}\)Js, 1eV = \( 1.6 \times 10^{-19}\)J, \(E_1\) = - 8.6eV, \(E_2\) = - 3.5eV, f = ?
ΔE = hf
f = \(\frac{ΔE}{h}\)
ΔE = \(E_2\) - \(E_1\) = - 3.5eV - (- 8.6eV) = 5.1eV
but 5.1eV = 5.1 X \( 1.6 \times 10^{-19}\) = \( 8.16 \times 10^{-19}\)J
f = \(\frac{8.16 \times 10^{-19}}{ 6.6 \times 10^{-34}}\)
Therefore, f = \( 1.24 \times 10^{15}\)Hz
longer than \(10^{-6} m\).
shorter than \(10^{-6} m\).
shorter than \(10^{3} m\).
longer than \(10^{3} m\).
Correct answer is A
The range of wavelengths for infrared waves is given as \(10^{-3}\) m to \(10^{-6}\)m. This means that the wavelength of the radiation is longer than \(10^{-6} m\) but shorter than \{10^{-3} m\). Therefore, the only correct option is that the wavelength is longer than \(10^{-6} m\).
\(30^0\)
\(60^0\)
\(45^0\)
\(0^0\)
Correct answer is C
Maximum Range R = \(\frac{u^2sin2\theta}{g}\)
maximum height H = \(\frac{u^2sin^2\theta}{2g}\)
But R : H = 4
\(\frac{u^2sin2\theta}{g}\) : \(\frac{u^2sin^2\theta}{2g}\) = 4
\(\frac{u^2sin2\theta}{g} \times\frac{2g}{u^2sin^2\theta}\) = 4
\(\frac{2sin2\theta}{sin^2\theta}\) = 4
since 2sinΘ = 2sinΘcosΘ
\(\frac{2 \times 2sin\theta cos\theta}{sin^2\theta}\) = 4
\(\frac{4sin\theta cos\theta}{sin^2\theta}\) = 4
\(\frac{sin\theta cos\theta}{sin^2\theta}\) = 1
\(\frac{cos\theta}{sin\theta}\) = 1
\(\frac{sin\theta}{cos\theta}\) = 1
\(tan \theta\) = 1
\(\theta = tan^{-1}1\) = 45°
A charge of 10 C is transferred across a potential difference of 220 V. Determine the work done.
22J
2200J
210J
230J
Correct answer is B
The work done in moving a charge across a potential difference is given by the formula W = QV, where W is the work done, Q is the charge and V is the potential difference. Substituting the given values, we get W = 10 C * 220 V = 2200 J. Hence, the work done is 2200 J.
1.550m
0.646m
5.120m
0.195m
Correct answer is B
f = 512Hz, V = 331m/s λ = ?
V = f λ
λ = \(\frac{v}{f} = \frac{331}{512}\)
λ = 0.646m.
The diagram above illustrates a velocity-time graph. Determine the distance between X and Y.
80.0m
160.0m
40.0m
10.0m
Correct answer is B
Distance between X and Y is the area of rectangular portion of the velocity-time graph.
XY = 40 × (8 - 4) = 40 × 4
∴ XY = 160 m
The type of mirror used by dentists to inspect the teeth of patients is a
Plane mirror
cylindrical mirror
concave mirror
convex mirror
Correct answer is C
The type of mirror used by dentists to inspect the teeth of patients is a concave mirror.
Concave mirrors are curved inwards and produce a magnified image of the object placed within its focus and pole. This is why dentists use concave mirrors to examine teeth, as it allows them to see the teeth in more detail.
Which of the following statements about a ferromagnetic material is correct? It
has a high susceptibility.
attracts non-magnetic materials.
has low relative permeability.
repels other magnetic materials.
Correct answer is A
The correct statement about a ferromagnetic material is:
It has a high susceptibility.
Ferromagnetic materials are characterized by having a high susceptibility, which means they are strongly attracted to magnetic fields. When placed in a magnetic field, ferromagnetic materials become magnetized and can themselves exhibit strong magnetic properties, attracting other magnetic materials. Ferromagnetic materials, such as iron, nickel, and cobalt, are commonly used in the construction of permanent magnets and electromagnets due to their strong response to magnetic fields.
II, III and IV
II only
I, II and III only
I only
Correct answer is B
According to Newton's third law of motion, the force exerted on the bus by the towing vehicle is of the same magnitude as the force exerted on the towing vehicle by the bus (Statement II). The other statements are not necessarily true.
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