Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

2,441.

If the refractive index of a medium is V2, what is the critical angle?

A.

45o

B.

50o12'

C.

56o25'

D.

75o

E.

90o

Correct answer is A

sin C = \(\frac{1}{n}\) ; sin C = \(\frac{1}{√2}\)

C = sin-1\(\frac{1}{√2}\)

= 45o

2,442.

A rod of length 10cm is heated through 100oC and its final length is 10.26cm. What is the co-efficient of linear expansion of the rod?

A.

0.026 per degree centigrade

B.

0.00026 per degree centigrade

C.

0.26 per degree centigrade

D.

1.0026 per degree centigrade

E.

0.0026 per degree centigrade

Correct answer is B

\(\alpha\) = \(\frac{L_2 - L_1}{L_1 \times \theta}\)

= \(\frac{10 - 26 - 10}{10 \times 100}\)

= 2.6 x 10-4oC

2,443.

Why does a piece of cork float on water?

A.

there is no upthrust on it when completely immersed in water

B.

the upthrust on it when completely immersed in water is greater than its weight in air

C.

the upthrust on it when completely immersed in water is less than its weight in air

D.

its specific gravity is greater than that of water

E.

its specific gravity is the same as that of water

Correct answer is B

It floats because it weighs more than amount of water it would have to push out of the glass if it sank. This means, its weight in air is less than its upthrust.

2,444.

The combination of sound waves with different frequencies is known as

A.

interference

B.

diffraction

C.

superposition

D.

forced vibration

E.

resonance

Correct answer is C

No explanation has been provided for this answer.

2,445.

An object 15cm high is 30cm from pin-hole camera. If the height of the image formed at the back of the camera is 10cm, the image distance is

A.

20cm

B.

45cm

C.

54cm

D.

63cm

E.

70cm

Correct answer is A

\(\frac{\text{image height}}{\text{object height}}\) = \(\frac{\text{image distance}}{\text{object distance}}\)

\(\frac{10}{15}\) = \(\frac{\text{image distance}}{30}\)

image distance = 20cm